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erastova [34]
3 years ago
14

How can i use multiplication to find the quotient 3/5÷3/15How can I use multiplication to find the quotient 3/5÷3/15

Mathematics
2 answers:
lapo4ka [179]3 years ago
7 0

\bf \cfrac{a}{b}\div \cfrac{c}{d}\implies \cfrac{a}{b}\cdot \cfrac{ d}{c}\qquad therefore \qquad \cfrac{3}{5}\div \cfrac{3}{15}\implies \cfrac{3}{5}\cdot \cfrac{15}{3}\implies \cfrac{3}{3}\cdot \cfrac{15}{5}\implies 3

mars1129 [50]3 years ago
3 0

The rule here is that one inverts (finds the reciprocal of) the divisor (3/15) and then multiplies:

In 3/5÷3/15

we arrive at 3/5 * 15/3 = 3.

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joja [24]

Answer:

<h3>Answer 3</h3>

\to 5 \times \dfrac{3}{4}  \\  \\  \to  \dfrac{5 \times 3}{4} \\  \\  \to  \dfrac{15}{4} \\  \\  \to \pmb{ 3 \dfrac{3}{4}}

<h3>Answer 4 :</h3>

\to 2 \times 1 \dfrac{1}{2}  \\  \\  \to 2 \times\dfrac{3}{2}  \\  \\ \to  \dfrac{2 \times 3}{2}  \\  \\ \to  \dfrac{6}{2}  \\  \\ \to  \pmb{3}

8 0
2 years ago
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A point $(x, y)$ with integer coordinates is randomly selected such that $0 \le x \le 8$ and $0 \le y \le 4$. what is the probab
ahrayia [7]

Answer:

\frac{1}{3}

Step-by-step explanation:

A point (x, y) with integer coordinates is randomly selected such that 0 \le x \le 8 \:and\: $0 \le y \le 4$.

The possible pairs of (x,y) are:

(0,0),(0,1),(0,2),(0,3),(0,4)

(1,0),(1,1),(1,2),(1,3),(1,4)

(2,0),(2,1),(2,2),(2,3),(2,4)

(3,0),(3,1),(3,2),(3,3),(3,4)

(4,0),(4,1),(4,2),(4,3),(4,4)

(5,0),(5,1),(5,2),(5,3),(5,4)

(6,0),(6,1),(6,2),(6,3),(6,4)

(7,0),(7,1),(7,2),(7,3),(7,4)

(8,0),(8,1),(8,2),(8,3),(8,4)

The Total Possible Outcomes n(S)= 45

The pair (x, y) that satisfies the given condition (say event A: x + y \le 4) are:

(0,0),(0,1),(0,2),(0,3),(0,4)\\(1,0),(1,1),(1,2),(1,3)\\(2,0),(2,1),(2,2)\\(3,0),(3,1)\\(4,0)

n(A)=15

Therefore:

P(A)=\frac{n(A)}{n(S)} =\frac{15}{45} =\frac{1}{3}

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Step-by-step explanation:

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