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Otrada [13]
2 years ago
6

How do the expressions 8+k2−6 and 8(k+2)−4k compare when k = 7?

Mathematics
1 answer:
Eva8 [605]2 years ago
7 0

Answer:

8(k+2)-4k>8+2k-6

Step-by-step explanation:

To figure out how they compare, we can substitute 7 into the equation:

8+(7)2-6\\8+14-6\\22-6\\16\\

8((7)+2)-4(7)\\8(9)-28\\72-28\\44

As you can see from the answers we got, 8(k+2)-4k>8+2k-6, when k=7.

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