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Sliva [168]
3 years ago
7

The two conditional relative frequency tables show the results of a neighborhood survey on the number and types of gardens in th

e community. A 4-column table with 3 rows titled garden-type frequencies by column. The first column has no label with entries flower garden, no flower garden, total. The second column is labeled vegetable garden with entries 0. 28, 0. 72, 1. 0. The third column is labeled no vegetable garden with labels 0. 22, 0. 78, 1. 0. The fourth column is labeled total with entries 0. 25, 0. 75, 1. 0. Table B: Garden-Type Frequencies by Row A 4-column table with 3 rows titled garden-type frequencies by row. The first column has no label with entries flower garden, no flower garden, total. The second column is labeled vegetable garden with entries 0. 56, 0. 48, 0. 5. The third column is labeled no vegetable garden with labels 0. 44, 0. 52, 0. 5. The fourth column is labeled total with entries 1. 0, 1. 0, 1. 0. Which table could be used to answer the question "Assuming someone has a flower garden, what is the probability they also have a vegetable garden?" Table A, because the given condition is that the person has a flower garden. Table A, because the given condition is that the person has a vegetable garden. Table B, because the given condition is that the person has a flower garden. Table B, because the given condition is that the person has a vegetable garden.
Mathematics
1 answer:
umka2103 [35]3 years ago
4 0

Answer:

...what :V

Step-by-step explanation:

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Answer:

b=\dfrac{1}{5}a.

Step-by-step explanation:

We need to write an  equation for the amount of chemical B as a function of the amount of chemical A.

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where, k is constant of proportionality.

It is given that fifteen grams of chemical A is used to produce 3 grams of chemical B. It means a=15 and b=3.

Substitute a=15 and b=3 in (1).

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k=\dfrac{3}{15}=\dfrac{1}{5}

Substitute k=\dfrac{1}{5} in (1).

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