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Inga [223]
2 years ago
6

In a card game, the probability that you will have a hand with three of a kind is about 6%. The dealer wants to know the probabi

lity for a player to be dealt three of a kind by at least the second hand. Should a geometric probability density function or a cumulative distribution function be used? Explain.
A geometric cumulative distribution function should be used because the question asks for the probability for a player to be dealt three of a kind by at least the second hand.
A geometric probability density function should be used because the question asks for the probability for a player to be dealt three of a kind by at least the second hand.
A geometric cumulative distribution function should be used because the question states that the probability for having a hand with three of a kind is about 6%.
A geometric probability density function should be used because the question states that the probability for having a hand with three of a kind is about 6%.
There is not enough information to be to able to determine whether a geometric probability density function or a cumulative distribution function should be used.
Mathematics
1 answer:
ELEN [110]2 years ago
7 0

Answer:

its not D :)

Step-by-step explanation:

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WHY CAN'T ANYONE HELP ME PLEASE?? The Pool Fun Company has learned​ that, by pricing a newly released Fun Noodle at $3, sales wi
Zinaida [17]

Answer:

  y = -1000x +11000

Step-by-step explanation:

<u>Given:</u>

  (x, y) = (sales price, number sold) = (3, 8000), (6, 5000)

<u>Find</u>:

  slope-intercept equation for a line through these points

<u>Solution</u>:

When given two points, it often works well to start with the 2-point form of the equation for a line.

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Filling in the given points, you have ...

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  y = -1000x +11000 . . . . the desired equation

6 0
3 years ago
What is the answer ?
MrRissso [65]
Answer is B.  thank me l8ter

6 0
3 years ago
Find the arc length of a central angle 300 degrees in a circle whose radius is 2 inches? help now ASP I NEED HELP A.10 π/ 3 in
NeTakaya
\text{Arc length } =  \frac{\theta}{360}2\pi r

=  (\frac{300}{360})2\pi (2)

=  4\pi(\frac{300}{360})

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5 0
3 years ago
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JulsSmile [24]

Answer:

About 1.5 or 1

Step-by-step explanation:

Divide 14 by 9 to get the answer

please vote and rate

8 0
3 years ago
Read 2 more answers
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