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Radda [10]
3 years ago
10

Find h r=4 l=9 im lost

Mathematics
1 answer:
Sphinxa [80]3 years ago
6 0
I Think The answer is33
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One more i need help with plz answer I need it done by today
polet [3.4K]

Answer:187.5 inches.

Step-by-step explanation:

25 / 2 = x / 15

25 = 2x / 15

15(25) = 2x

375 = 2x

187.5 = x

The actual car is 187.5 inches.

5 0
3 years ago
Read 2 more answers
Examine the diagram. It is not drawn to scale.
Readme [11.4K]
119 as c=62 A=61 so
7 0
2 years ago
(I need the answer right now please) ΔA'B'C' was constructed using ΔABC and line segment EH. 2 triangles are shown. Line E H is
irina1246 [14]

Answer:

The true statements are

1. BD = DB'

3. m∠EFA = 90°

4. The line of reflection, EH, is the perpendicular bisector of BB', AA', and

   CC'

Step-by-step explanation:

* Lets explain how to solve the problem

- Reflection is flipping an object over the line of reflection.

- The object and its image have the same shape and size, but the

  figures are in opposite directions from the line of reflection

- The objects appear as if they are mirror reflections, with right and left

  reversed

- The line of reflection is a perpendicular bisector for all lines joining

  points on the figure with their corresponding images

- Look to the attached figure for more understand

* Lets solve the problem

- ΔA'B'C' was constructed using ΔABC and line segment EH, where

 EH is the reflection line

- D is the mid-point of BB'

- F is the mid-point of AA'

- G is the mid-point of CC'

* Lets find from the answer the true statements

1. BD = DB'

∵ D is the mid point of BB'

- Point D divides BB' into two equal parts

∴ BD = DB' ⇒ <em>True</em>

2. DF = FG

- It depends on the size of the sides and angles of the triangle

∵ We can't prove that

∴ DF = FG ⇒ <em>Not true</em>

3. m∠EFA = 90°

∵ The line of reflection ⊥ the lines joining the points with their

   corresponding images

∴ EH ⊥ AA' and bisect it at F

∴ m∠EFA = 90° ⇒ <em>True</em>

4. The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC'

- Yes the line of reflection is perpendicular bisectors of them

∴ The line of reflection, EH, is the perpendicular bisector of BB',

   AA', and CC' ⇒ <em>True</em>

5. ΔABC is not congruent to ΔA'B'C'

∵ In reflection the object and its image have the same shape and size

∴ Δ ABC is congruent to Δ A'B'C'

∴ ΔABC is not congruent to ΔA'B'C' ⇒ <em>Not true</em>

4 0
3 years ago
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1.9 x (1/4) answer as a fraction
Elan Coil [88]

Answer:

19/40 1.9x0.25=0.475= 19/40

7 0
3 years ago
What is 4 radical 3 divided by 2?
Arte-miy333 [17]
3/2 = 6 
6/4= 6/40= 6 .999= ~ 7
5 0
3 years ago
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