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anyanavicka [17]
2 years ago
14

A phone company advertises a new plan in which the customer pays a fixed amount of $ 25 per month for unlimited calls in the cou

ntry and $ 0.10 per minute for international calls . If a customer paid 120 dollars , how many international minutes did they use ?
Mathematics
2 answers:
marusya05 [52]2 years ago
4 0

Answer: The answer would be 950 international minutes. Only if assuming that this is in one month since the question doesn't give much detail.

Step-by-step explanation:

X would be used to represent the number of months.

25+0.10x=120

0.10x=95

950 international minutes used

Nataly_w [17]2 years ago
4 0

Answer:

950

Step-by-step explanation:

An equation to model this scenario would be: y = 0.1x + 25

y would mean the amount of money paid depending on x, which is the number of minutes.

In this problem, we know the amount of money. So we know y is 120.

We can then put 120 into the equation to find x.

120 = 0.1x +25  

95 = 0.1x

x = 950

Therefore, x is 950.

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Answer:

A

Step-by-step explanation:

3 0
2 years ago
What is the value of (20−1+52−0)−1×5
lara [203]
<span>19+52−0−(1)(5)</span>
<span><span><span>71−0</span>−<span><span>(1)</span><span>(5)
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4 0
3 years ago
A salesperson's weekly paycheck is 50% more than a second salesperson's paycheck. The two paychecks total $1625. Find the amount
USPshnik [31]

Answer:

The amount of each person's pay check =

a = First person's pay check = $1083.33

b = Second person's pay check = $541.67

Step-by-step explanation:

Let first sales person's pay check = a

The second sales person's pay check = b

A salesperson's weekly paycheck is

50% more than a second salesperson's paycheck.

Hence,

First pay check (a) = a

Second paycheck (b) = 0.5 of a

= 0.5a

The two paychecks total $1625.

a + b = $1625

a + 0.5a = 1625

1.5a = 1625

a = 1625/1.5

a =$ 1083.3333333

a is approximately = $1083.33

Since

0.5a = b

0.5 × 1083.3333333 = b

$541.66666667 = b

b = approximately = $541.67

Therefore, the amount of each person's pay check approximately to the nearest cent =

a = First person's pay check = $1083.33

b = Second person's pay check = $541.67

6 0
3 years ago
A box contains 16 ​transistors, 5 of which are defective. if 5 are selected at​ random, find the probability that
ExtremeBDS [4]
Part (a): All are defective
Only one way of selecting the 5 defective transistors:

Number of ways of selections available = 6C5 = 16!/[5!*(15-5)!] = 4368

Probability they are all defective = Number of ways of selecting 5 defectives/Total number of ways possible = 1/4368 ≈ 0.000229

Part (b): None are defective
Total number of non defectives = 16 -5 = 11
Number of ways of selecting 5 non defective = 11C5 = 462 ways
Total number of ways possible = 16C5 = 4368
Probability of selecting 5 non defectives = 462/4368 = 11/104 ≈ 0.1058


5 0
3 years ago
Read 2 more answers
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