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2 years ago

Which statements are true about Gretchen's adjusted data set?

Mathematics

2 answers:

Brilliant_brown [7]2 years ago

8 0

Answer:

The spread values are closer to the spread values of Manuel’s data set.

The data set is approximately symmetric.

The data set is skewed left.

Step-by-step explanation:

i got it right.

GenaCL600 [577]2 years ago

6 0

Answer:

The spread values are closer to the spread values of Manuel’s data set.

The data set is approximately symmetric.

The data set is skewed left.

Step-by-step explanation:

Its right on edmentum

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Find the Perimeter of this shape. Can someone explain to me how to find the perimeter.

Agata [3.3K]

The little lines in each side show that the sides are the same length but you also need to find the length of the smaller side which isn’t the same. For this imagine that the shape is split into a square and a triangle and you need to find the long side of the triangle using Pythagoras
a^2 + b^2 = c^2
20^2 + 20^2 = 800
Square root of 800 = 28.3
Then do 28.3-20=8.3
So I think the answer is 20+20+20+20+20+8.3=108.3 cm

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3 years ago

Rajit buys 4 pairs of socks for $2.50 per pair. He pays with a $20 bill.

sveta [45]

2.50 x 4 = 10

20 - 10 = 10

so his change would be $10

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3 years ago

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A certain city's population is 120,000 and decreases 1.4% per year for 15 years.

mart [117]

Answer:

Decay Problem.

Decay rate, r = 0.014
Initial Amount =120,000

$P(t)=120000(0.986)^t$
P(10)=104,220

Step-by-step explanation:

The exponential function for growth/decay is given as:

$P(t)=P_0(1 \pm r)^t, where:\\P_0$ is the Initial Population\\r is the growth/decay rate\\t is time$

In this problem:

The city's initial population is 120,000 and it decreases by 1.4% per year.

Since the population decreases, it is a Decay Problem.

Decay rate, r=1.4% =0.014
Initial Amount =120,000

Therefore, the function is:

$P(t)=120000(1 - 0.014)^t\\P(t)=120000(0.986)^t$

When t=10 years

$P(10)=120000(0.986)^10\\=104219.8\\\approx 104220 $ (to the nearest whole number)$

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3 years ago

Calvin had 30 minutes in time-out. For the first 23 1/3 minutes, Calvin counted spots on the ceiling. For the rest of the time,

scoundrel [369]

Answer: $\frac{20}{3}\ minutes$ or $6 \frac{2}{3}\ minutes$

Step-by-step explanation:

For this exercise you can convert the mixed number to an improper fraction:

1. Multiply the whole number part by the denominator of the fraction.

2. Add the product obtained and the numerator of the fraction (This will be the new numerator).

3. The denominator does not change.

Then:

$23\frac{1}{3}= \frac{(23*3)+1}{3}= \frac{70}{3}\ minutes$

You know that he had 30 minutes in time-out, he counted spots on the ceiling for $\frac{70}{3}$ minutes and the rest of the time he made faces at his stuffed tiger.

Then, in order to calculate the time Calvin spent making faces at his stuffed tiger, you need to subract 30 minutes and $\frac{70}{3}$ minutes:

$30\ min-\frac{70}{3}=(\frac{3(30)-70}{3})=\frac{20}{3}\ minutes$ or $6 \frac{2}{3}\ minutes$

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3 years ago

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What is the value of x?

ser-zykov [4K]

X = 20

Isolate the variable by dividing each side by factors that don't contain the variable.
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3 years ago

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