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marin [14]
3 years ago
13

Classify the pair of angles, (complementary, supplementary, or vertical), then find the value of X.

Mathematics
1 answer:
Kruka [31]3 years ago
3 0

Answer:

30 | Vertical?

Step-by-step explanation:

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A boat has a speed of 15 mph in still water. It travels downstream from Greentown to Glenavon in g hours. It then goes back upst
valentina_108 [34]

Answer:

The distance from Greentown to Glenavon is D1 = g*(15+x) miles downstream.

The distance from Glenavon to Cambria is D2 = g*(15-x) miles upstream.

The difference D1 - D2 is 2 miles, according to the condition.

It gives you an equation g*(15+x) - g*(15-x) = 2, which you can easily solve and find "x", the rate of the current. x = 1/g miles per hour.

7 0
3 years ago
HELP!!!In the expression 100 a/b, if a is greater than b, which statements are true? b ≠ 0. Select all that apply.
MAXImum [283]

Answer:

\large\boxed{\text{The expression is equal to}\ \sqrt[b]{100^a}}\\\boxed{\text{The expression is greater than 100}}

Step-by-step explanation:

a^\frac{m}{n}=\sqrt[n]{a^m}\\\\\text{True statement:}\\\\100^\frac{a}{b}=\sqrt[b]{100^a}\\\\a>b\to\dfrac{a}{b}>1\to\dfrac{a}{b}=1\dfrac{a-b}{b}\\\\100^\frac{a}{b}=100^{1\frac{a-b}{b}}=100^{1+\frac{a-b}{b}}=100^1\cdot100^\frac{a-b}{b}=100\sqrt[b]{100^{a-b}}\\\\a>b\to a-b>0\to100^{a-b}>1\\\\\text{Therefore}\ 100\sqrt[b]{100^{a-b}}>100

4 0
3 years ago
Factorise quadratic equation<br> n^2-n=0
Sindrei [870]

n² - n = 0

n(n-1)

\\  \\

7 0
3 years ago
2x + 5y = 16<br> y + 4x = 3
masha68 [24]

Answer:

If your solving for x on the first one it’s x =−5/2y+8

If your solving for y on the second one it’s y =−4x+3

Step-by-step explanation:

5 0
3 years ago
I WILL AWARD BRAINLIEST!! PLEASE HELP!!!<br> Find the areas of the trapezoids.
Galina-37 [17]

Answer:

A = 12 units ^2

Step-by-step explanation:

The area of the trapezoid is found by

A = 1/2 (b1+b2)h

b1 = 2

b2 = 4

h = 4

I found these by looking at the graph

A = 1/2(2+4) 4

A = 1/2(6*4)

A = 12 units ^2

8 0
3 years ago
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