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Mnenie [13.5K]
2 years ago
11

Which equation best fits the graphed data?

Mathematics
1 answer:
fenix001 [56]2 years ago
6 0

Answer:

hmm

Step-by-step explanation:

lettt meee thinkkkkkk

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A sociologist studying freshmen carried out a survey, asking, among other questions, how often students went out per week, how m
IgorC [24]

Answer:

This is called Simpson's Paradox.

Therefore the correct option is A.) Simpson's Paradox.

Step-by-step explanation:

i) This is called Simpson's Paradox.

ii) If there are trends that tend to appear in several different groups of data which apparently either disappear or tend to reverse when these data groups are combined.

4 0
3 years ago
in an examination, Adenike obtained 19marks more than musa.if adenike had obtained one and half times her own mark,she would hav
fomenos

Answer: Adenike scored 64 marks, while Musa scored 45 marks

Step-by-step explanation: We shall start by assigning letters to each unknown variable. Let Adenike’s mark be d while Musa’s mark shall be m.

First of all, if Adenike obtained 19 marks more than Musa, then if Musa scored m, Adenike would score 19 + m (or d = 19 + m). Also if Adenike has obtained one and half her own mark (which would be 1 1/2d or 3d/2), it would have been equal to 6 times more than twice Musa’s mark (or 6 + 2m). This can be expressed as

3d/2 = 6 + 2m. So we now have a pair of simultaneous equations;

d = 19 + m ———(1)

3d/2 = 6 + 2m ———(2)

Substitute for the value of d into equation (2), if d = 19 + m

(3{19 + m})/2 = 6 + 2m

By cross multiplication we now have

3(19 + m) = 2(6 + 2m)

57 + 3m = 12 + 4m

We collect like terms and we have

57 - 12 = 4m - 3m

45 = m

We now substitute for the value of m into equation (1)

d = 19 + m

d = 19 + 45

d = 64

So Adenike scored 64 marks while Musa scored 45 marks

6 0
4 years ago
Match each pair of points to the equation of the line that is parallel to the line passing through the pointsB(5,2) and C(7,-5)Y
a_sh-v [17]

we will select each points and find equation of line

option-A:

points are B(5,2) and C(7,-5)

x1=5,y1=2 , x2=7 , y2=-5

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-5-2}{7-5}

m=-3.5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-2=-3.5(x-5)

y=\frac{-7}{2}x+\frac{39}{2}...........Answer

option-B:

points are D(11,6) and E(5,9)

x1=11,y1=6 , x2=5 , y2=9

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{9-6}{5-11}

m=-0.5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-6=-0.5(x-11)

y=\frac{-1}{2}x+\frac{23}{2}...........Answer

option-C:

points are F(-7,12) and G(3,-8)

x1=-7,y1=12 , x2=3 , y2=-8

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-8-12}{3+7}

m=-2

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-12=-2(x+7)

y=-2x-2...........Answer

option-D:

points are H(4,4) and I(8,9)

x1=4,y1=4 , x2=8 , y2=9

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{9-4}{8-4}

m=1.25

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-4=1.25(x-4)

y=\frac{5}{4}x-1...........Answer

option-E:

points are J(7,2) and K(-9,8)

x1=7,y1=2 , x2=-9 , y2=8

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{8-2}{-9-7}

m=-\frac{3}{8}

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y-2=\frac{3}{8}(x-7)

y=\frac{3}{8}x-\frac{5}{8}...........Answer

option-F:

points are L(5,-7) and M(4,-12)

x1=5,y1=-7 , x2=4 , y2=-12

Firstly, we will find slope

m=\frac{y_2-y_1}{x_2-x_1}

we can plug values

m=\frac{-12+7}{4-5}

m=5

we can use point slope form of line

y-y_1=m(x-x_1)

we can plug values

y+7=5(x-5)

y=5x-32...........Answer



7 0
3 years ago
Read 2 more answers
The expression cos 4xcos 3x +sin 4r sin 3x is<br> equivalent to
iris [78.8K]

Answer:

Step-by-step explanation:

cos 4x cos 3x+ sin 4x sin 3x=cos(4x-3x)=cos x

8 0
3 years ago
Mrs. Poster's class is divided into three groups of students. Each group has 3 girls and 2 boys, Which expression could she use
natka813 [3]

Answer:

3 X (2+3)

Step-by-step explanation:

If we have five students (3 girls and 2 boys), and three groups, we can use the expression 3 X (2+3), which concludes three groups times five students (in each group), which will give us our total of 15 students.

6 0
3 years ago
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