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2 years ago

I will give up to 40 points if you help answer 5 questions

Mathematics

2 answers:

sergey [27]2 years ago

7 0

Answer:

SSS
the answer is A
SAS
1, 2, 3, 4, and 5
using alternate interior angles theorem on angles A and C, verticle angles theorem on angle O, and the Parallelogram Diagonals Theorem Converse you can prove triangles ADO and BOC are similar. Then using CPCTC "Corresponding parts of congruent triangles are congruent" you can prove that line segment AO is congruent (equal) to line segment CO

Step-by-step explanation:

if my answer helps plz give me brainliest :)

Shtirlitz [24]2 years ago

5 0

Answer:

I hope this helps. I'm sorry in advance if it isn't.

Step-by-step explanation:

1) SSS

2) The first bullet point

3) SAS

4) They are congruent by SAS, ASA

5) Segment AO is congruent to segment CO because:

The diagonals AC and BD both have O as the intersection point. AC = BD since the geometric means of the legs is equal. Thus AO is congruent to CO

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Answer: I believe you answered your own question 21.

Step-by-step explanation: Logan will drive 7×3 or 21miles in 7 hours

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3 years ago

Can somebody please explain and answer this for me? I really don't get it.

Tcecarenko [31]

Answer:

Results can be $(-\frac{1}{3} )^5$

Step-by-step explanation:

-The solution for this question:

$(-\frac{1}{3} )^5$ is equal to $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$ × $(-\frac{1}{3})$

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3 0

3 years ago

A group of friends are at a baseball game and are purchasing souvenirs. Dustin purchased 5 t-shirts and 1 baseball cap, spending

Inessa [10]

Answer:

Shirt-$19

Cap-$24

Step-by-step explanation:

5s+1c=119

1s+1c=43

1c=43-1s

substitute:

5s+(43-1s)=119

5s+43-1s=119

4s=119-43

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7 0

3 years ago

The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t

shtirl [24]

Answer:

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

Step-by-step explanation:

As the given Augmented matrix is

$\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 1 :

$r_{1}$ ↔ $r_{1} - r_{2}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]$

Step 2 :

$r_{3}$ ↔ $r_{3} - 8r_{1}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]$

Step 3 :

$r_{2}$ ↔ $\frac{r_{2}}{7}$

$\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]$

Step 4 :

$r_{1}$ ↔ $r_{1} + 14r_{2}$ , $r_{3}$ ↔ $r_{3} - 124r_{2}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]$

Step 5 :

$r_{3}$ ↔ $\frac{r_{3}. 7}{254}$

$\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]$

Step 6 :

$r_{1}$ ↔ $r_{1} - 4r_{3}$ , $r_{2}$ ↔ $r_{2} + \frac{1}{7} r_{3}$

$\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]$

∴ we get

$x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\$

6 0

3 years ago

25 points to whoever solves the whole page

faust18 [17]

Answer:

row 1

-9

-19

-13

row 2

-2

row 3

-3

-11

-7

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers