Question

Need help with number 7

Answer 1

Cheap answer, multiply both sides by the LCD, in this case 2, that way, you get rid of the denominators.

$\bf 5x-\cfrac{1}{2}(3x+8)=-4-\cfrac{7}{2}x\impliedby \times \stackrel{LCD}{2} \\\\\\ \boxed{2}\cdot 5x-\boxed{2}\cdot \cfrac{1}{2}(3x+8)=-\boxed{2}\cdot 4-\boxed{2}\cdot \cfrac{7}{2}x \\\\\\ 10x-(3x+8)=-8-7x\implies 10x-3x-8=-8-7x \\\\\\ 7x-8=-8-7x\implies 14x=-8+8\implies 14x=0 \\\\\\ x=\cfrac{0}{14}\implies x=0$