Which of the following equations has no solution?
1 answer:
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Given:
f(x) = x²
g(x) = 4x²
Therefore
g(x) = 4f(x)
This means that the value of g(x) is 4 times the value of f(x). So the graph og (x) is the graph of f(x) vertically stretched by a factor of 4.
The graph shown below confirms the conclusion.
Answer: C.
The graph of g(x) is the graph of f(x) vertically stretched by a factor of 4.
f(x) = x²
g(x) = 4x²
Therefore
g(x) = 4f(x)
This means that the value of g(x) is 4 times the value of f(x). So the graph og (x) is the graph of f(x) vertically stretched by a factor of 4.
The graph shown below confirms the conclusion.
Answer: C.
The graph of g(x) is the graph of f(x) vertically stretched by a factor of 4.
Answer:
Horizontal asymptote of the graph of the function f(x) = 16x/(3+x^2) is y=0
Step-by-step explanation:
I attached the graph of the function. Graphically it can be seen that the horizontal asymptote of the graph of the function is y=0.
When denominator's degree (2) is higher than nominator's degree (1) then the horizontal asymptote is y=0
