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dmitriy555 [2]
2 years ago
7

How do I know which substance is being reduced? ​

Chemistry
1 answer:
Llana [10]2 years ago
8 0
When an atoms oxidation number decreases in a reaction then it’s being reduced. the answer for that question is B
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Calculate the number of photons that would be contained in a laserpulse with a wavelength of 287 nm that contained 4.35 mJ of en
OLEGan [10]

Answer:

3.46 ⋅ 10 − 19 J

Explanation:

The energy of a photon is proportional to its frequency,

4 0
3 years ago
Consider an electron with charge −e−e and mass mmm orbiting in a circle around a hydrogen nucleus (a single proton) with cha
PtichkaEL [24]

Answer:

Explanation:

The net force on electron is electrostatic force between electron and proton in the nucleus .

Fc = \frac{1}{4\pi\epsilon} \times \frac{e\times e}{r^2}

This provides the centripetal force for the circular path of electron around the nucleus .

Centripetal force required = \frac{m\times v^2}{r}

So

\frac{m\times v^2}{r}=\frac{1}{4\pi\epsilon} \times \frac{e\times e}{r^2}

v^2=\frac{e^2}{4\pi \epsilon m r}

v=(\frac{e^2}{4\pi \epsilon m r})^{\frac{1}{2} }

5 0
2 years ago
4 outer planets in order
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Jupiter, Saturn, Uranus, Neptune, Jovian... is your answer. 
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2 years ago
Read 2 more answers
Butane (C4 H10(g), Hf = –125.6 kJ/mol) reacts with oxygen to produce carbon dioxide (CO2 , Hf = –393.5 kJ/mol ) and water (H2 O,
WITCHER [35]

Answer: Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

Explanation:

The chemical equation for the combustion of butane follows:

2C_4H_{10}(g)+4O_2(g)\rightarrow 8CO_2(g)+10H_2O(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(8\times \Delta H^o_f_{CO_2(g)})+(10\times \Delta H^o_f_{H_2O(g)})]-[(1\times \Delta H^o_f_{C_4H_{10}(g)})+(4\times \Delta H^o_f_{O_2(g)})]

We are given:

\Delta H^o_f_{(C_4H_{10}(g))}=-125.6kJ/mol\\\Delta H^o_f_{(H_2O(g))}=-241.82kJ/mol\\\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(CO_2(g))}=-393.5kJ/mol\\\Delta H^o_{rxn}=?

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(8\times -393.5)+(10\times -241.82)]-[(2\times -125.6)+(4\times 0)]\\\\\Delta H^o_{rxn}=-5315kJ

Enthalpy of combustion (per mole) of C_4H_{10} (g) is -2657.5 kJ

6 0
2 years ago
In terms of shape and volume, how can a gas be defined ?
Gnoma [55]

Particles in a gas are far apart compared to a solid or liquid, allowing it not to have a definitive shape or volume. This also means that gases can fill any container and be easily compressed.

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2 years ago
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