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ipn [44]
3 years ago
7

Solve this polynomial:

Mathematics
2 answers:
d1i1m1o1n [39]3 years ago
7 0

hope it helps

plz mark brainliest

musickatia [10]3 years ago
4 0

Answer:

Step-by-step explanation:

7j^3 - 2 + 5j^3 - j - 3

12j^3 - j - 5

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Step-by-step explanation:

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3 years ago
Jay had 6 times as much money as Kay. Then Jay gave Kay $33. Jay now has twice as much money as Kay. How much did they each star
timofeeve [1]

Answer:

Jay started with $148.5 and Kay with $24.75.

Step-by-step explanation:

With the information provided you know that Jay had 6 times as much money as Kay wich can be expressed as:

J=6K, where

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K is the money Kay had

Also, you know that  Jay gave Kay $33 and Jay now has twice as much money as Kay, which would be:

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Now, you can replace J=6K in this equation and solve for K:

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Then, you can replace the value of K in J=6K:

J=6*24.75

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According to this, the answer is that Jay started with $148.5 and Kay with $24.75.

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