Answer:
4 x^(3/2) + 5x -32
Step-by-step explanation:
This problem involves definite integration (anti-derivatives).
If dy/dx = 6x^(1/2) - 5, then dy = 6x^(1/2)dx - 5dx.
(1/2) + 1
This integrates to y = 6x
----------------
(1/2) + 1 x^(3/2)
= 6 ------------ + C
3/2
or: 4 x^(3/2) + C
and the ∫5dx term integrates to 5x + C.
The overall integral is:
4 x^(3/2) + C + 5x + C. better expressed with just one C:
4 x^(3/2) + 5x + C
We are told that the curve represented by this function goes thru (4, 20).
This means that when x = 4, y = 20, and this info enables us to find the value of the constant of integration C:
20 = 4 · 4^(3/2) + 5·4 + C, or:
20 = 4 (8) + 20 + C
Then 0 = 32 + C, and so C = -32.
The equation of the curve is thus 4 x^(3/2) + 5x -32
(1/2 + 1)
It is false am pretty sure
He walked 3 miles in an hour. He would have to also walk 9 laps in 45 minutes to walk the same amount. Not sure what your question is?
