Question

In the figure below,ABC is an isosceles triangle with |AB|=|AC|.|BC| is extended to D such that |AC|=|CD|.If ​

Answer 1

The perimeter of the triangle ABC is $10+\sqrt{10}$ $units$.

The given parameters:

• Triangle ABC = Isosceles triangle

The length of AC = 3-(-2) = 5 unit

The length of AC = length of BC = 5 unit

The length of BC is calculated by applying Pythagoras theorem as follows;

$BC^2=(4-1)^2+(3-2)^2$

$BC^2=3^2+1^2$

$BC^2=10$

$BC=\sqrt{10}$

The perimeter of the triangle ABC is calculated as follows;

$P=AB+AC+BC$

$P=5+5+\sqrt{10}$

$P=10+\sqrt{10$  $units$

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