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statuscvo [17]
3 years ago
10

The diagram shows a dilation of segment AB. Which

Mathematics
2 answers:
xz_007 [3.2K]3 years ago
4 0

Answer:

A. the dilation is an enlargement

C. the point O is the center of dilation

E. the sale factor is 9

Step-by-step explanation:

i just did it

Alenkasestr [34]3 years ago
3 0

Answer:

A. The dilation is an enlargement

C. Point O is the center of dilation

D. The scale factor is 3

Step-by-step explanation: right on edge

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6 times what would = 73
padilas [110]

Answer:

12.1 repeating

Step-by-step explanation:

73/6=12.16666666...

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3 years ago
What is the value of 3/4 increased by 2 1/6?
Mashutka [201]

Answer:

2 11/12

Step-by-step explanation:

3/4 + 2 1/6

Add the fractions.

35/12

= 2 11/12

8 0
3 years ago
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CAN SOMEONE PLSSS HELP ME! IT’S DUE TODAY. I NEED THE SURFACE AREA AND VOLUME...
aev [14]

Answer:

Surface \ area = 2 (LB + BH + HL) = 2 ((4\times 8)+(8 \times 6) + (6 \times 4))

                                                     = 2(32 + 48 + 24)\\=2(104) \\=208 cm^2

Volume = L \times B \times H = 4 \times 8 \times 6 = 192cm^3

8 0
3 years ago
A container manufacturer plans to make rectangular boxes whose bottom and top measure 2x by 3x. The container must contain 12in.
lisabon 2012 [21]

The height of the container be so as to minimize cost will be 1.20. inches.

<h3>How to calculate the height?</h3>

The volume of the box will be:

= 2x × 3x × h

= 6x²h

Volume = 6x²h

12 = 6x²h

h = 2x²

The cost function will be:

C = 2.60(2)(6x²) + 4.30(12x)h

C = 31.2x² + 51.6xh

Taking the derivative

62.4x + 51.6h

h = 1.20

Therefore, the height of the container be so as to minimize cost will be 1.20 inches.

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5 0
2 years ago
A cylindrical package to be sent by a postal service can have a maximum combined length and girth (perimeter of a cross section)
dolphi86 [110]

Answer:

radius r = 47/π in

length l = 23.5 in

Step-by-step explanation:

Let us recall that:

Volume of a cylinder = \pi r^2 h --- (1)

The girth g = 2 \pi r + h      ----- (2)

Given that:

height (h) + girth (g) = 141

Then g = 141 - h   ----- (3)

Equating equation (2) and (3), we have:

141 - h = 2πr + h

2h = 141 - 2πr

h = 70.5 - πr      ------ (4)

From, here now, we can now replace the value of h into equation (1)

i.e.

V = πr²(70.5 - πr)

V = 70.5πr² -  π²r³

Taking the differential of the above equation with respect to r, we have:

\dfrac{dv}{dr} = 141 \pi r- 3\pi ^2 r^2

By further differentiation:

\dfrac{d^2v}{dr^2} = 141 \pi - 6\pi ^2 r

Let set \dfrac{dv}{dr}= 0, Then:

141πr - 3π²r² = 0

141πr = 3π²r²

Divide both sides by πr

141 = 3πr

r = 141/3π

r = 47/π in

Replacing the value of r = 47/π into equation (4), we have:

h = 70.5 - πr

h = 70.5 - π(47/π)

h = 70.5 - 47

h = 23.5 in

From equation (3);

h + g = 141

23.5 + g = 141

g = 141 - 23.5

g = 117.5 in

Volume = πr²h

V = π × (47/π )² × 23.5

V = 16523.94 in³

4 0
3 years ago
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