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Mama L [17]
2 years ago
11

Solve the following please:

Mathematics
1 answer:
dalvyx [7]2 years ago
8 0

Answer:

most likely b

Step-by-step explanation:

the more than symbol tells me that it is going to move past 10.

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find two consecutive odd integers that 7 times the smaller integer is 61 more than 2 times the larger integer.
Aleks04 [339]

Answer:

x = 13     smaller integer

x + 2 = 15  the other integer

Step-by-step explanation:

x = the smaller integer

x + 2 = the next integer          

7(x) = 61 + 2(x + 2)

7x = 61 + 2x +4

5x = 61 + 4

5x  = 65

x = 13     smaller integer

x + 2 = 15  the other integer

8 0
3 years ago
When each side of an equation has been simplified, equations that have BLANK coefficients and BLANK constants on each side have
kobusy [5.1K]

Answer:

The answer is below

Step-by-step explanation:

An equation shows the relationship between two or more variables. An equation is a statement that shows the equality between expressions. An equation with infinitely many solution is when all numbers are solutions, that is there is no one solution. Example is: x + 3 = x + 3.

When each side of an equation has been simplified, equations that have the same coefficients and the same constants on each side have infinitely many solutions

7 0
3 years ago
There are 30 students in a class and 40% of the class like orange juice how many studesnt love orange juice
Dovator [93]
What is 40% of 30?

first, convert the percent into a decimal
40% = 0.4

then multiply 0.4 with 30

30*0.4 = 12

12 students

any questions?


6 0
3 years ago
5 times a number is 14 less than the square of that number. Find the positive solution.
anastassius [24]

Write the word problem in algebraic form:

n2 -14 = 5n

Write as a quadratic:

n2 - 5n - 14 = 0

Factor:

(n+2)(n-7) = 0

Solve:

n+2 = 0    =>   n = -2

n-7 = 0    =>   n = 7

positive solution is 7.   (14 less than 72 = 35 which is also 5 times 7)

8 0
4 years ago
Read 2 more answers
Im pulling my hair out with this problem my calculator simplified it to <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%2B%2F-%5Cs
Tamiku [17]

~~~~~~~~~~~~\textit{quadratic formula} \\\\ 0=\stackrel{\stackrel{a}{\downarrow }}{3}x^2\stackrel{\stackrel{b}{\downarrow }}{+2}x\stackrel{\stackrel{c}{\downarrow }}{-5} \qquad \qquad x= \cfrac{ - b \pm \sqrt { b^2 -4 a c}}{2 a} \\\\\\ x= \cfrac{ - (2) \pm \sqrt { (2)^2 -4(3)(-5)}}{2(3)} \implies x = \cfrac{ -2 \pm \sqrt { 4 +60}}{ 6 } \\\\\\ x= \cfrac{ -2 \pm \sqrt { 64 }}{ 6 }\implies x=\cfrac{ -2 \pm 8}{ 6 }\implies x= \begin{cases} ~~ 1\\ -\frac{5}{3} \end{cases}

6 0
2 years ago
Read 2 more answers
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