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solniwko [45]
2 years ago
9

Select the correct answer from each drop-down menu. In a voltaic cell, the electrons and is oxidized, while the electrons and is

reduced.
Chemistry
1 answer:
KengaRu [80]2 years ago
3 0

Given what we know, we can confirm that in a voltaic cell, the anode loses electrons and is oxidized, meanwhile, the cathode is reduced by gaining electrons.

<h3 /><h3>What is a voltaic cell?</h3>
  • It is described as an electrochemical cell.
  • These cells use chemical reactions to produce electrical energy.
  • During this reaction, an anode loses electrons, thus oxidizing.
  • Meanwhile, the cathode gains electrons and is reduced.

Therefore, given the nature of the voltaic cell, we can confirm that during its reaction, the anode is oxidized by losing electrons while the cathode becomes reduced by gaining them.

To learn more about electrical energy visit:

brainly.com/question/863273?referrer=searchResults

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In a test of an automobile engine 1.00 L of octane (702 g) is burned, but only 1.84 kg of carbon dioxide is produced. What is th
Reptile [31]

Answer:

The % yield of CO2 is 85.05 %

Explanation:

Step 1: Data given

Mass of octane = 702 grams

Molar mass octane = 114.23 g/mol

Mass CO2 =1.84 kg = 1840 grams

Molar mass of CO2

Step 2: The balanced equation

2C8H18 + 25O2 → 16CO2 + 18H2O

Step 3: Calculate moles of octane

Moles octane = mass octane / molar mass octane

Moles octane = 702.0 grams / 114.23 g/mol

Moles octane = 6.145 moles

Step 4: Calculate moles of CO2

For 2 moles octane we need 25 moles O2 to produce 16 moles CO2 and 18 moles H2O

For 6.145 moles octane we'll have 8*6.145 moles =49.16 moles

Step 5: Calculate mass of CO2

Mass CO2 = moles CO2 * molar mass CO2

Mass CO2 = 49.16 moles * 44.01 g/mol

Mass CO2 = 2163.5 grams

Step 6: Calculate % yield of carbon dioxide

% yield = (actual yield / theoretical yield)*100%

% yield = (1840/2163.5)*100%

% yield = 85.05 %

The % yield of CO2 is 85.05 %

4 0
3 years ago
There are 6 different organisms in the picture above. Organize them into 2 or more groups AND defend your groups by
anyanavicka [17]

Answer:

thay all are different from each other

5 0
3 years ago
Nitrogen dioxide typically results from the oxidation of nitrogen monoxide in air. If 6.2 mols of N2 react, how many moles of NO
xz_007 [3.2K]

Answer: The mass of oxygen that combines with nitrogen will be 2.272g.

Explanation:

5 0
3 years ago
The ph of a solution containing 0.818 M acetic acid<br> (ka1.76*10-5) ans 0.172 M sodium acetate is?
kvasek [131]

Explanation:

It is known that the relation between pH and pK_{a} is as follows.

              pH = pK_{a} + log \frac{[salt]}{[acid]}

and,     pK_{a} = -log K_{a}

Hence, first we will calculate the value of pK_{a} as follows.

                   pK_{a} = -log K_{a}

                               = -log (1.76 \times 10^{-5}

                               = 4.75

Now, we will calculate the value of pH as follows.

              pH = pK_{a} + log \frac{[\text{sodium acetate}]}{\text{acetic acid}}

                    = 4.75 + log \frac{0.172}{0.818}      

                    = 4.75 + (-0.677)

                    = 4.07

Therefore, we can conclude that the pH of given solution is 4.07.

5 0
3 years ago
How many moles of HCl would react with 37.1 mL of 0.138 M Sr(OH)2
Lena [83]

Answer is: 0.102 moles of HCl would react.

Balanced chemical reaction:

2HCl(aq) + Sr(OH)₂ → SrCl₂(aq) + 2H₂O(l).

V(Sr(OH)₂) = 37.1 mL ÷ 1000 mL/L.

V(Sr(OH)₂) = 0.0371 L; volume of the strontium hydroxide solution.

c(Sr(OH)₂) = 0.138 M; molarity of the strontium hydroxide solution.

n(Sr(OH)₂) = c(Sr(OH)₂) · V(Sr(OH)₂).

n(Sr(OH)₂) = 0.0371 L · 0.138 mol/L.

n(Sr(OH)₂) = 0.0051 mol; amount of the strontium hydroxide.

From balanced chemical reaction: n(Sr(OH)₂) : n(HCl) = 1 : 2.

n(HCl) = 2 · n(Sr(OH)₂).

n(HCl) = 2 · 0.0051 mol.

n(HCl) = 0.0102 mol; amount of the hydrochloric acid.

5 0
3 years ago
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