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Ne4ueva [31]
2 years ago
9

Which bonds form in the reaction shown in the diagram?

Chemistry
2 answers:
lesya692 [45]2 years ago
7 0

Explanation:

The bond between C and O in CO₂ and O and H in H₂O

Therefore,

Option C is correct✔

Fed [463]2 years ago
3 0

Answer:

C.) is correct. your answer might be different depending on the wording of the question

Explanation:

:p

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Formula los siguientes compuesto: Dietil eter, Etanol, Propanotriol, Acido Propanodioico, Pentanal, Pentano-2,4-diona, Metanoato
viva [34]

Answer:

Explanation:

En este caso para formular los compuestos, debes identificar el grupo funcional principal de la molecula. Una vez que eso está hecho, puedes intentar formularlo.

Empezaremos primero identificando el grupo funcional principal de la molécula, para luego formularlo correctamente.

Dietil eter: la terminación eter al final significa que pertenece al grupo de los éteres, el cual tiene como formula general R - O - R.

Etanol: debido a que termina en ol, este grupo pertenece a los alcoholes. Para formularlo solo se dibuja la molecula del etano, junto a un enlace con el grupo OH, como su formula general R - OH.

Propanotriol: igualmente termina en ol, por lo tanto es un alcohol, sin embargo, en este caso, tambien tiene la terminación prefija tri, asi que significa que hay 3 grupos OH en la molecula.

Acido propanodioico: esta es sencilla, porque empieza como acido, y solo hay un grupo funcional que empieza así y son los acidos carboxilicos, es decir, el grupo COOH (R - COOH) que es el carboxilo. Tiene el prefijo di, antes del oico, por lo que son dos carboxilos presentes en la molecula.

Pentanal: el sufijo al, significa que pertenece al grupo de los aldehidos, en este caso, posee el grupo carbonilo H - C = O.

Pentano - 2,4 - diona: la terminación ona significa que pertenece al grupo de las cetonas, (R - CO - R), parecido a los aldehidos, con la diferencia de que tiene grupos alquilos en lugar de un hidrogeno.

Metanoato de metilo: la terminación ato de ilo, pertenece a los esteres, (R - COOR) derivado de los acidos carboxilicos.

De aqui en adelante solo mencionaré los grupos funcionales pues ya se explicó el por que, por sus terminaciones:

Ciclohexano - 1.3 - diol: este pertenece a los alcoholes.

Acido heptanoico: acido carboxilico

Ciclobutil metil eter: eteres

Acetato de etilo: ester

2-metilbenzaldehído: aldehído unido a un grupo aromatico como el benceno.

Ciclohexanona: un ciclo (cadena cerrada) unido a un grupo carbonilo.

Butanona: cetona.

Observa la foto adjunta para que veas la formulación de cada una:

6 0
3 years ago
What property of argon is uses in light bulbs?
otez555 [7]
<span>The filament of the light bulb will get very hot. This will encourage a chemical reaction with most gases that are surrounding that filament - and the result is that the filament burns out. If the filament is in air, it combines with the carbon of carbon dioxide in the air, and the filament disintegrates. But argon is an inert gas - almost nothing reacts with it. So the filament takes a very long time (theoretically infinity) to burn out. But the bulb cannot contain 100% argon: 99.9% is typical; the remaining 0.1% being air. The bulb manufacturers can control the 'life' of a bulb, based on that principle: they do not want their bulbs to last forever!</span>
8 0
3 years ago
Read 2 more answers
What is the percent composition by mass of oxygen in ca(no3)2 (gram-formula mass = 164 g/mol)?a.9.8%b.29%c.48%d.59%?
Mila [183]
Percent composition by mass of oxygen =
((16.0*6)/(40.1+2*(14.0+16.0*3)))*100%
= 58.5%
therefore, the answer is D
8 0
3 years ago
Read 2 more answers
If a man has a mass of 83 kilograms on Earth, what will the force of gravity on his body be on the moon? A. 135.6 N B. 318.5 N C
diamong [38]
First, we need to know what's the gravity value in the moon. it is 1.622 m/ s2

to find the force, let's recall this formula----> Force= mass x gravity

force= 83 kg x 1.622= 134.6

A is the closest choice.
4 0
3 years ago
Read 2 more answers
Comparing the 2-bromobutane + methoxide and 2-bromobutane + t-butoxide reactions, choose the statements that BEST describe the d
Elina [12.6K]

Answer:

an increase in 1-butene was observed when t-butoxide was used

Explanation:

When a base reacts with an alkyl halide, an elimination product is formed. This reaction is an E2 reaction.

Here we are to compare the reaction of two different bases with one substrate; 2-bromobutane. Both reactions occur by the E2 mechanism but follow different transition states due to the size of the base.

The Saytzeff product, 2-butene, is obtained when the methoxide is used while the non Saytzeff product, 1-butene, is obtained when t-butoxide is used.

The Saytzeff rule is reliable in predicting the major products of simple elimination reactions of alkyl halides given the fact that a small/strong bases is used for the elimination reaction. Therefore hydroxide, methoxide and ethoxide bases give similar results for the same alkyl halide substrate. Bulky bases such as tert-butoxide tend to yield a higher percentage of the non Saytzeff product and this is usually attributed to steric hindrance.

8 0
3 years ago
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