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2 years ago

Please help me worth 35 points!!

Mathematics

2 answers:

mixer [17]2 years ago

7 0

Answer:

Solution given:

Volume of rectangular prism=length*breadth*height

for

1st one 4in,3in,6in

Volume=4*3*6=72cu.in

For second one 6in,3in,2in

Volume=6*3*2=36cu.in

For third one 4in ,5in,4in

Volume=4*5*4=80cu.in

For forth one 2in,9in,3in

Volume=2*9*3=54cu.in

KonstantinChe [14]2 years ago

7 0

Answer:

The answer

Step-by-step explanation:

1. 72cu in; 6*4*3

2. 36 cu in; 6*3*2

3. 80 cu in;4*5*4

4. 54 cu in;9*2*3

You just have to muiltply L*W*H ( length times width time height)

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Condense the following logs into a single log:

mamaluj [8]

QUESTION 1

The given logarithm is

$8\log_g(x)+5\log_g(y)$

We apply the power rule of logarithms; $n\log_a(m)=\log_(m^n)$

$=\log_g(x^8)+\log_g(y^5)$

We now apply the product rule of logarithm;

$\log_a(m)+\log_a(n)=\log_a(mn)$

$=\log_g(x^8y^5)$

QUESTION 2

The given logarithm is

$8\log_5(x)+\frac{3}{4}\log_5(y)-5\log_5(z)$

We apply the power rule of logarithm to get;

$=\log_5(x^8)+\log_5(y^{\frac{3}{4}})-\log_5(z^5)$

We apply the product to obtain;

$=\log_5(x^8\times y^{\frac{3}{4}})-\log_5(z^5)$

We apply the quotient rule; $\log_a(m)-\log_a(n)=\log_a(\frac{m}{n} )$

$=\log_5(\frac{x^8\times y^{\frac{3}{4}}}{z^5})$

$=\log_5(\frac{x^8 \sqrt[4]{y^3} }{z^5})$

7 0

3 years ago

Find the perimeter of the triangle. 16% + 16) cm (9%-11) cm

maxonik [38]

Answer:

Step-by-step explanation:

Three equal sides, so lets find one by solving for x

6x + 16 = 9x-11

-3x = -27

x = 9

6(9) + 16 = 70

9(9) - 11 = 70

70(3) = 210 cm

8 0

3 years ago

What is the image of (-9,-5) after a dilation by a scale factor of 5 centered at the origin?

Novosadov [1.4K]

Answer:

$(-45,-25)$

Step-by-step explanation:

$-9 * 5 = -45-5 * 5 = -25(-45,-25)$

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2 years ago

How many gallons each of 20% alcohol and 10% alcohol should be mixed to obtain 10gal of 11% alcohol?

Scilla [17]

Answer:

20% alcohol = 1 gal

10% alcohol = 9 gal

Step-by-step explanation:

Let

x = 20% alcohol

y = 10% alcohol

x + y = 10 (1)

0.20x + 0.10y = 10*0.11

0.20x + 0.10y = 1.1 (2)

From (1)

x = 10 - y

Substitute x = 10 - y into (2)

0.20x + 0.10y = 1.1

0.20(10 - y) + 0.10y = 1.1

2 - 0.20y + 0.10y = 1.1

- 0.20y + 0.10y = 1.1 - 2

-0.10y = -0.9

y = -0.9/-0.10

y = 9 gal

substitute y = 9 into (1)

x + y = 10

x + 9 = 10

x = 10 - 9

x = 1 gal

20% alcohol = 1 gal

10% alcohol = 9 gal

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3 years ago

Find the volume of a square pyramid 13 m tall whose base measures 5 m on a side

goblinko [34]

$a=5m;\ H=13m\\\\The\ volume\ of\ a\ square\ pyramid:V=\frac{1}{3}a^2H\\\\Subtitute\ the\ values\ of\ a\ and\ H:\\\\\boxed{V=\frac{1}{3}\cdot5^2\cdot13=\frac{1}{3}\cdot25\cdot13=\frac{325}{3}=108\frac{1}{3}\ (m^3)}$

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3 years ago