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Anton [14]
2 years ago
14

Please help me worth 35 points!!

Mathematics
2 answers:
mixer [17]2 years ago
7 0

Answer:

Solution given:

Volume of rectangular prism=length*breadth*height

for

1st one 4in,3in,6in

Volume=4*3*6=<u>72cu.in</u>

For second one 6in,3in,2in

Volume=6*3*2=<u>36cu.in</u>

For third one 4in ,5in,4in

Volume=4*5*4=<u>8</u><u>0</u><u>c</u><u>u</u><u>.</u><u>in</u>

For forth one 2in,9in,3in

Volume=2*9*3=<u>5</u><u>4</u><u>cu</u><u>.</u><u>in</u>

KonstantinChe [14]2 years ago
7 0

Answer:

The answer

Step-by-step explanation:

1. 72cu in; 6*4*3

2. 36 cu in; 6*3*2

3. 80 cu in;4*5*4

4. 54 cu in;9*2*3

You just have to muiltply L*W*H ( length times width time height)

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6 0
3 years ago
Helppp!!!! please!!!
Ulleksa [173]

Answer:

\boxed{Area = 32.5 mm^2}

Step-by-step explanation:

Area of Triangle = \frac{1}{2} (Base)(Height)

Where base = 13 mm, Height = 5 mm

Area = 1/2 (13)(5)

=> Area = 1/2 (65)

=> Area = 32.5 mm^2

5 0
3 years ago
Read 2 more answers
On a piece of paper, graph f(x)= x if x&lt;1
Deffense [45]

Answer:

B is the answer

Step-by-step explanation:

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3 years ago
A certain test preparation course is designed to help students improve their scores on the LSAT exam. A mock exam is given at th
Valentin [98]

Answer:

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12.8

The sample deviation calculated s=4.324 \approx 4.3

12.8-4.604\frac{4.324}{\sqrt{5}}=3.896    

12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704    

So on this case the 99% confidence interval would be given by (3.896;21.704)    

Step-by-step explanation:

Data: 10,9,20,13,12

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=12.8

The sample deviation calculated s=4.324

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.99 or 99%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,4)".And we see that t_{\alpha/2}=4.604

Now we have everything in order to replace into formula (1):

12.8-4.604\frac{4.324}{\sqrt{5}}=3.896    

12.8+ 4.604\frac{4.324}{\sqrt{5}}=21.704    

So on this case the 99% confidence interval would be given by (3.896;21.704)    

6 0
2 years ago
Add 2 1/3 + 4 5/8 write your answer as a mixed number
Yanka [14]
6+1/3+5/8
6+1x8/3x8+5x3/8x3
6+8/24+15/24
6+8+15/24
6 23/24

Answer: 6 23/24

5 0
2 years ago
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