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2 years ago

I need help on 8.02× 70

Mathematics

1 answer:

Leviafan [203]2 years ago

3 0

Lets solve this!

8.02 x 70 = 160.40.

Voila! Your answer is 160.40.

Hope this Helps!

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Help picture below problem 12

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Answer:

124°

Step-by-step explanation:

Not the best at explaining but should be equal to 180 straight across. You have to find the missing angle. You know the right angle is 90° so you will add 34° to get 124°. 180-124 will get you 56°. Straught across you have the angle that you are trying to find which is 124° because 180-56 is 124.

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2 years ago

Simplify each expression(OOF PLEASE HURRY FGHJHGFGHJ):

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3 years ago

P(x)=3x^4-2x^3+2x^2-1 what is the remainder when p(x) is divided by (x+1)

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Step-by-step explanation:

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3 years ago

Quadratics Help please?

irakobra [83]

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3 years ago

Read 2 more answers

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that $\pi = 0.2$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}$

$0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}$

$\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}$

$(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}$

$n = 5615$

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now $\pi = 0.12, n = 5615$ .

We have to find M.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 2.81\sqrt{\frac{0.12*0.88}{5615}}$

$M = 0.012$

7 0

2 years ago