I need help on 8.02× 70

El área del cuadrado que se forma sobre la hipotenusa del triángulo es...

exis [7]

Answer:

translate to English please

Step-by-step explanation:

so confused

4 0

3 years ago

What is the most precise name for the solid that can be formed from a net diagram of 6 congruent squares ?

Naily [24]

check the picture below.

4 0

3 years ago

30 points and BRAINLIEST!

Ghella [55]

Answer:

(x − 4)² + (y − 3)² = 25

Step-by-step explanation:

The equation of a circle is:

(x − h)² + (y − k)² = r²

Given three points on the circle, we can write three equations:

(1 − h)² + (7 − k)² = r²

(8 − h)² + (6 − k)² = r²

(7 − h)² + (-1 − k)² = r²

Expanding:

1 − 2h + h² + 49 − 14k + k² = r²

64 − 16h + h² + 36 − 12k + k² = r²

49 − 14h + h² + 1 + 2k + k² = r²

Simplifying:

50 − 2h + h² − 14k + k² = r²

100 − 16h + h² − 12k + k² = r²

50 − 14h + h² + 2k + k² = r²

Subtracting the first equation from the second and third equations:

50 − 14h + 2k = 0

-12h + 16k = 0

Solving the system of equations, first reduce:

25 − 7h + k = 0

-3h + 4k = 0

Solve with substitution or elimination. Using substitution, solve for k in the first equation and substitute into the second.

k = 7h − 25

-3h + 4(7h − 25) = 0

-3h + 28h − 100 = 0

25h = 100

h = 4

k = 7h −25

k = 7(4) − 25

k = 3

Now plug these into any of the original three equations to find r.

(1 − h)² + (7 − k)² = r²

(1 − 4)² + (7 − 3)² = r²

9 + 16 = r²

25 = r²

The equation of the circle is:

(x − 4)² + (y − 3)² = 25

Graph: desmos.com/calculator/ctoljeqhnp

6 0

3 years ago

(a) A parachutist lands at a point on the line between the points A and B, and the target is an operation at A. The operation fa

mr Goodwill [35]

Answer:

a) $\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}$

b) $P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736$

Step-by-step explanation:

Part a

We assume that the parachutist lands at random point in the interval (x=A,y=B) we have a continuous random variable X. And the distribution of X would be uniform $Y\sim Unif(A,B)$ . And the density function would be given by:

$f(x) =\frac{1}{B-A} , A$

And 0 for other case.

The operation fails, if parachutist's distance to A is more than five times as much as her distance to B.

So the point P in the interval (A,B) at which the distance to A is exactly 5 times the distance to B is given by:

$P= A + \frac{5}{6} (B-A)= \frac{6A +5B -5A}{6}=\frac{A+5B}{6}$

And we can find the probability desired like this:

$P(d(P,A) \geq 5 d(P,B))= P(\frac{A+5B}{6} < X< B)$

And from the cumulative distribution function of X ficen by $F(X)\frac{X-A}{B-A}$ we got:

$\frac{B-\frac{A+5B}{6}}{B-A}= \frac{6B -A-5B}{6(B-A)}=\frac{B-A}{6(B-A)}=\frac{1}{6}$

Part b

For this case we assume that $X\sim Gamma (2,1)$

On this case we assume that $\alpha=2, \beta= 1$

The density function for the Gamma distribution is given by:

$P(X)= \frac{\beta^{\alpha} x^{\alpha-1} e^{-\beta x}}{\gamma(\alpha)}$

And on this case we can find the probability using the complement rule like this:

$P(X>1) = 1-P(X\leq 1)=0.736$

We can solve this problem with the following excel code:

"=1-GAMMA.DIST(1;2;1;TRUE)"

And if we do it by hand we need to do this:

$P(X>1) = 1-P(X\leq 1)=1-\int_{0}^1 \frac{1^{2} x^{2-1} e^{- x}}{\gamma(2)}=0.736$

6 0

3 years ago

A sack of cement is enough to cover a floor with a total area of 45sqft Joel’s floor length is 8ft by 7ft how many sacks will he

borishaifa [10]

2 sack of cement is needed to cover entire floor of Joel

Solution:

Given that a sack of cement is enough to cover a floor with a total area of 45 sqft

Joel’s floor length is 8ft by 7ft

To find: Number of sacks needed to cover entire floor of Joel

Let us first find area of Joel's floor

Since the floor is generally of rectangular, we can use area of rectangle

$\text{ area of rectangle } = length \times width$

So the total area of floor with length 8 feet and width 7 feet is:

$\text{ area of floor } = 8 \times 7 = 56$

Thus the total area of floor is 56 square feet

Let us now find number of sacks needed to cover entire floor

Given that, one sack of cement covers 45 square feet

$\text{ number of sacks needed } =\frac{\text { total area of floor }}{\text { area covered by one sack }}$$

$\text{ number of sacks needed }=\frac{56}{45}=1.244$$

Since Sack of cement cannot be in point value hence we can say 2 sack of cement is required.

8 0

3 years ago