3 years ago

Solve the equation X+3y=13 X^2+3y^2=43

Mathematics

1 answer:

Assoli18 [71]3 years ago

3 0

Answers are 7/2;4 and 3;5/2

You might be interested in

Which of the following is equivalent to (x^4/3 x^2/3)^1/3

Reika [66]

Answer:

The answer is2nd point

Step-by-step explanation:

${n}^{a} \times {n}^{b} = {n}^{a + b}$

(x^4/3)×(x^2/3) = x^(4/3 + 2/3)

= x²

${( {n}^{a} )}^{b} = {n}^{ab}$

(x²)^1/3 = x^(2×1/3)

= x^2/3

7 0

3 years ago

Read 2 more answers

Anthony is now designing the classroom layout for the school. Each hallway has exactly 5 classrooms. If Anthony has 48 classes t

cluponka [151]

Answer:

9 and a half

Step-by-step explanation:

the fewest number is 9.5 because thats the exact amount in hallways that he needs

4 0

3 years ago

Read 2 more answers

Which shows one way to determine the factors of x - 9x2 + 5x – 45 by grouping?

EleoNora [17]

Answer:

The last one.

Step-by-step explanation:

6 0

3 years ago

Write the name of the period that has the digits 913 in 913256

solniwko [45]

I don't understand what your asking

8 0

3 years ago

Read 2 more answers

Help mee A scout troop are hiking in a forest. Starting from their base, they walk 4.2km south followed by 7.1km west. They want

slega [8]

Answer:

They should walk on a bearing of 59.4 degrees

Step-by-step explanation:

Given

$South = 4.2km$

$West = 7.1km$

Required

The bearing back to the base

The given question is illustrated with the attached image.

To do this, we simply calculate the measure of angle a using:

$\tan(a) = \frac{Opposite}{Adjacent}$

$\tan(a) = \frac{7.1}{4,2}$

$\tan(a) = 1.6905$

Take arctan of both sides

$a = \tan^{-1}(1.6905)$

$a = 59.4^o$

4 0

3 years ago