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2 years ago

A highly selective university will only admit students who place at least 2-zcores above the mean on the ACT that

Mathematics

1 answer:

Harrizon [31]2 years ago

3 0

Answer:

Step-by-step explanation:

Each z-score = 1 standard deviation from the mean, so 18 + (6 x 2) = 30

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Write the equation of this circle in standard form

Svetradugi [14.3K]

Answer:

Standard equation of this circle is (x +5)² + y² = 9.

Step-by-step explanation:

The equation of a circle with center at (h,k) and a radius of r is:

(x - h)² + (y - k)² = r²

Subtitute the variables with h= -5, k = 0, and r = 3

(x - (-5))² + (y - 0)² =3²

(x + 5)² + y² = 9

Pls mark as brainliest...

8 0

2 years ago

Round 0.832 to the nearest hundredth.

kodGreya [7K]

Answer:

0.83

Step-by-step explanation:

5 or more raise the score 4 or less let it rest

Elementary nostoligia :)

3 0

3 years ago

Read 2 more answers

The daily demand for ice cream cones at a price of $1.20 per cone is 50 cones. At a price of $2.20 per cone, the demand is 30 co

Lapatulllka [165]

Answer:

<h2>The demand at a price of $1.50 per cone is 44 cones</h2>

Step-by-step explanation:

let us apply the interpolation formula to solve this problem

we have

$\frac{y-y1}{x-x1} =\frac{y2-y1}{x2-x1}$

Now let us set the values to the notation above

x= $1.20

x1= $2.20

x2= $1.50

y = 50 cones

y1= 30 cones

y2= ?

$y2= \frac{(y-y1)}{(x-x1)} (x2-x1)+y1$

Substituting our given data we have

$y2= \frac{(50-30)}{(1.2-2.2)} (1.5-2.2)+30\\\\y2= \frac{20}{-1} (-0.7)+30\\\\y2= (20*0.7)+30\\y2= 14+30\\y2= 44$

the demand at a price of $1.50 per cone is 44 cones

4 0

2 years ago

In the rolling of two fair dice calculate the following: P(Sum of the two dice is 7) = ______

vesna_86 [32]

Answer:

P(Sum of the two dice is 7) = 6/36

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

A fair dice can have any value between 1 and 6 with equal probability. There are two fair dices, so we have the following possible outcomes.

Possible outcomes

(first rolling, second rolling)

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)

(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)

(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)

(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)

(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)

(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

There are 36 possible outcomes.

Desired outcomes

Sum is 7, so

(1,6), (6,1), (5,2), (2,5), (3,4), (4,3).

There are 6 desired outcomes, that is, the number of outcomes in which the sum of the two dice is 7.

Answer

P(Sum of the two dice is 7) = 6/36

7 0

3 years ago

A ramp with a constant incline is made to connect a driveway to a front door. At a point 4 feet from the driveway, the height of

harkovskaia [24]

Let A(4,12) and B(6,18)

RATE OF CHANGE = m = (y₂ - y₁) / (x₂ - x₁) = (18-12)/ (6-4)

m= 6/2 or m = 3

4 0

2 years ago

Read 2 more answers