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pochemuha
3 years ago
7

The sum of the measures of three adjacent angles is 150°. The measures of the angles are in the ratio of ​1:2:3. What is the mea

sure, in degrees, of the largest angle?
The measure of the largest angle is degrees.
Mathematics
1 answer:
stellarik [79]3 years ago
8 0

Answer:

14•4°

step by step explanation:

ratio=1:2:3=6

angles in degree=150°

6/150°×360°(simplify)

6/5°×12°

=72°/5°

=14•4°

The largest angle=14•4°

Thanks hope it helps

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The mean number of goals scored is 2.5.
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Answer:

2 games.

Step-by-step explanation:

2.5 + 1.8 = 4

4 divided by 2 = 2

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3 years ago
A. Transform F using the rule (x, y) → (-x, y) (1 pt.)
serg [7]

Answer:

A: (-3,4) (-3,6) (-5,6) (-7,4)

B: The transformation would be described as a reflection over the y axis

C:  The transformation does result in a congruent figure because the shape doesn't change in size or shape and in length or width

Step-by-step explanation:

So our plots from the figure are: (3,4)  (3,6)  (5,6)  (7,4)

So using the rule (x, y) → (-x, y) are new points would be:

(-3,4)

(-3,6)

(-5,6)

(-7,4)

This rule (x, y) → (-x, y) is used for the type of transformation that is a reflection but over the y axis.

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2 years ago
I NEED help with my homework. I don’t get it
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Help with what part I can help
7 0
3 years ago
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A store has been selling 300 Blu-ray disc players a week at $600 each. A market survey indicates that for each $40 rebate offere
timurjin [86]

Answer:

75 $

Step-by-step explanation:

According to problem statement p(300) = 600

And we know that with a rebate of 40 $, numbers of units sold will increase by 80 then if x is number of units sold, the increase in units is

(  x  - 300 )  , and the price decrease

(1/80)*40  =  0,5

Then the demand function is:

D(x)  =  600  - 0,5* ( x - 300 )  (1)

And revenue function is:

R(x) =  x * (D(x)   ⇒   R(x) =  x* [  600  - 0,5* ( x - 300 )]

R(x) = 600*x  - 0,5*x * ( x - 300 )

R(x) = 600*x - 0,5*x² - 150*x

R(x) = 450*x  - (1/2)*x²

Now taking derivatives on both sides of the equation we get

R´(x) =  450  - x

R´(x) =  0       ⇒   450  - x = 0

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We can observe that for   0 < x  < 450  R(x) > 0 then R(x) has a maximum for x = 450

Plugging this value in demand equation, we get the rebate for maximize revenue

D(450)  =  600  - 0,5* ( x - 300 )

D(450)  =  600 - 225 + 150

D(450)  =

D(450)  =  600 - 0,5*( 150)

D(450)  =  600 - 75

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600 - 525  = 75 $

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