side of the triangle = 12 inches
side of the square = 8 inches
12 is 4 more than 8
perimeter of the square = 4(8) =32 inches
perimeter of the triangle = 3(12) = 36 inches
36 is 4 more than 32
Let T= side of the triangle and S = side of the square
3T = 4S+4
T=S+4
3(S+4) = 4S+4
3S+12 = 4S +4
4S-3S = S = 12-4 = 8
T =8+4 = 12
Answer:
D
Step-by-step explanation:
2x + 4 > 16
Subtract 4 from both sides
2x > 12
Divide both sides by 2
x > 6
The area of a triangle is given by one-half base times height. So...
56 = 0.5bh
We can divide both sides by 0.5 to isolate the bh...
112 = bh
Now to find all the possible combinations for the base and height, we need to find the factors of 112. They are 1, 2, 4, 7, 8, 14, 16, 28, 56, 112.
So the possible sets are:
1 and 112
2 and 56
4 and 28
7 and 16
8 and 14
Hope this helps :)
Answer:
20
Step-by-step explanation:
The sides of the 4-sided figure are the same length, so we can find the perimeter (sum of side lengths) by multiplying one side length by 4.
<h3>Side length</h3>
Points F(-2, -2) and G(-2, 3) lie on the same vertical line: x = -2. The distance between them is the difference of their y-coordinates:
FG = (3 -(-2)) = 5
Each side is 5 units long.
<h3>Perimeter</h3>
The length of the four sides is ...
P = 4s = 4(5) = 20
The perimeter of the rhombus is 20 units.
