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Tamiku [17]
2 years ago
15

A pet store has three aquariums for fish. Aquarium A contains 24 fish, Aquarium B contains 51 fish, and Aquarium C contains 36 f

ish. Which of the following graphs would represent this data most accurately? The y-axis of a bar graph starts at zero fish. One bar is 24 units, another bar is 51 units, and the third bar is 36 units. A pictograph shows three cubes. One cube has a side length of 8, another cube has a side length of 17, and the third cube has a side length of 12. The y-axis of a bar graph starts at 20 fish. One bar is 24 units, another bar is 51 units, and the third bar is 36 units. A pictograph shows three squares. One square has a side length of 2.4, another square has a side length of 5.1, and the third cube has a side length of 3.6. ill give brainliest to whoever actually answers first!!!!!
Mathematics
1 answer:
bazaltina [42]2 years ago
5 0

The graph that can represent the data most accurately is (a) The y-axis of a bar graph starts at zero fish. One bar is 24 units, another bar is 51 units, and the third bar is 36 units

The given parameters are:

  • Aquarium A: 24 fishes
  • Aquarium B: 51 fishes
  • Aquarium C: 36 fishes

The above dataset can be represented on a bar graph, where the lengths of the bars represent the number of fishes in each aquarium

Hence, the graph that can represent the data most accurately is (a)

Read more about graphs at:

brainly.com/question/25677468

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Step-by-step explanation:

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How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo
kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

s = \frac{d}{t}

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so s = 299,792.458

(a) San Francisco (about 500km)

Find t when d = 500. So

s = \frac{d}{t}

299,792.458 = \frac{500}{t}

299,792.458t = 500

t = \frac{500}{299,792.458}

t = 0.0017s

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when d = 10,000. So

s = \frac{d}{t}

299,792.458 = \frac{10,000}{t}

299,792.458t = 10,000

t = \frac{10,000}{299,792.458}

t = 0.033s

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when d = 400,000. So

s = \frac{d}{t}

299,792.458 = \frac{400,000}{t}

299,792.458t = 400,000

t = \frac{400,000}{299,792.458}

t = 1.334s

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that d = 44,879,361.3. So:

s = \frac{d}{t}

299,792.458 = \frac{44,879,361.3}{t}

299,792.458t = 44,879,361.3

t = \frac{44,879,361.3}{299,792.458}

t = 149.7s

It takes 149.7s for the light to reach Venus.

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Plug in 4 for x and solve equation like so. c=2

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