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3 years ago

a lottery game has balls numbered 1 through 21. what is the probability of selecting a ball with a prime number on it or a 10

Mathematics

2 answers:

Ronch [10]3 years ago

6 0

Answer:

3/7

Step-by-step explanation:

The prime numbers that lie between 1 and 21 are 2,3,5,7,11,13,17, and 19. These 8 balls, plus the 10-ball comes to a total of 9 balls that could be picked out of the 21. Therefore, the probability of picking one of these balls is 9/21 or 3/7

Vinil7 [7]3 years ago

5 0

Answer:

$\frac{9}{21}$

Step-by-step explanation:

→ List the prime numbers between 1 and 21

2, 3, 5, 7, 11, 13, 17 and 19

→ Count how many ball that is

8 balls

→ Remember in the question it says "what is the probability of selecting a ball with a prime number on it or a 10"

8 balls + 1 ball (the one with the number 10)

→ 9 balls overall over a total of 21

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Choice A. Next

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nordsb [41]

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3 years ago

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Dvinal [7]

Answer:

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

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10y = - 6x + 8 ( divide each term by 10 )

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3 years ago

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Solve each system by elimination 5x+y=9 10x-7y=-18 -4x+9y=9 x-3y=-6

tiny-mole [99]

5x + y = 9....multiply by 7
10x - 7y = -18
----------------
35x + 7y = 63 (result of multiplying by 7)
10x - 7y = -18
----------------add
45x = 45
x = 45/45
x = 1

5x + y = 9
5(1) + y = 9
5 + y = 9
y = 9 - 5
y = 4

solution is : (1,4)
=========================
-4x + 9y = 9
x - 3y = -6 ....multiply by 4
----------------
-4x + 9y = 9
4x - 12y = -24 (result of multiplying by 4)
---------------add
- 3y = - 15
y = -15/-3
y = 5

x - 3y = -6
x - 3(5) = -6
x - 15 = -6
x = -6 + 15
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solution is : (9,5)

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3 years ago