a lottery game has balls numbered 1 through 21. what is the probability of selecting a ball with a prime number on it or a 10

Mathematics

2 answers:

Ronch [10]3 years ago

6 0

Answer:

3/7

Step-by-step explanation:

The prime numbers that lie between 1 and 21 are 2,3,5,7,11,13,17, and 19. These 8 balls, plus the 10-ball comes to a total of 9 balls that could be picked out of the 21. Therefore, the probability of picking one of these balls is 9/21 or 3/7

Vinil7 [7]3 years ago

5 0

Answer:

$\frac{9}{21}$

Step-by-step explanation:

→ List the prime numbers between 1 and 21

2, 3, 5, 7, 11, 13, 17 and 19

→ Count how many ball that is

8 balls

→ Remember in the question it says "what is the probability of selecting a ball with a prime number on it or a 10"

8 balls + 1 ball (the one with the number 10)

→ 9 balls overall over a total of 21

You might be interested in

The length of the hypotenuse of a right triangle is 13 m. the length of one leg is 5 cm. find the length of the other leg

eimsori [14]

A^2 + B^2=C^2 so there for the hypotenuse (13^2) - (5^2) will give you the last side

7 0

2 years ago

A triangle has sides of 18cm and 32cm. The measurement of the longest side is missing. Ted says that one possibility for the unk

gulaghasi [49]

Since the measurement of the longest side is missing we can use the pythagorean theorem to find the hypotenuse or longest side.

18^2 + 32^2 = c (hypotenuse) ^2
324 + 1,024 = c^2
1,348 = c^2
sqrt 1,348 = c
36.72 = c
i do not agree with ted because when you use the pythagorean theorem you do not get 47cm

this can be proved by
18^2 + 32 ^2 = 47^2
we already know the left side is 1,348
1,348 = 47^2
1,348 does not equal 2,209 which is 47 squared

4 0

3 years ago

Christian and Yong had some stickers in the ratio 2:3. After Yong gave Christian 15 stickers, the ratio became 5:7. What was the

Snezhnost [94]

Answer:

15:23

step-by-step explanation:

6 0

2 years ago

Find the surface area of the right rectangular shown below hurry plss

laila [671]

Surface area of a cuboid