The dimensions of the rectangle can be a length of 2ft and a width of 4ft.
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How to find the dimensions of the garden?</h3>
Remember that for a rectangle of length L and width W, the perimeter is:
P = 2*(L + W)
And the area is:
A = L*W
In this case, we know that the area is 8 square feet and the perimeter is 12 ft, then we have a system of equations:
12ft = 2*(L + W)
8ft² = L*W
To solve this, we first need to isolate one of the variables in one of the equations, I will isolate L on the first one:
12ft/2 = L + W
6ft - W = L
Now we can replace that in the other equation to get:
8ft² = (6ft - W)*W
This is a quadratic equation:
-W^2 + 6ft*W - 8ft² = 0
The solutions are given by Bhaskara's formula:
Then we have two solutions:
W = (-6 - 2)/-2 = 4ft
W = (-6 + 2)/-2 = 2ft
If we take any of these solutions, the length will be equal to the other solution.
So the dimensions of the rectangle can be a length of 2ft and a width of 4ft.
if you want to learn more about rectangles:
brainly.com/question/17297081
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Answer:
“The true mean weight of the piglets is at most 39lbs”would be the alternate hypothesis.
Step-by-step explanation:
Given that the null hypothesis of an experiment is “The true mean weight of the piglets is at least 39lbs”
We have to find the alternate hypothesis.
In hypothesis testing, alternate is the opposite of null hypothesis. If null hypothesis supports one statement alternate hypothesis opposes it. In other words, alternate hypothesis would be the negative of the claim of null hypothesis.
Here the null hypothesis of an experiment is “The true mean weight of the piglets is at least 39lbs”
i.e H0: 
So alternate hypothesis
Ha: 
-17 as negative values become less as its debt.
For example...
if you have a mixed fraction 1 1/2, and change it to fraction greater than one, it would be 3/2 (which is 1 or 2/2 + 1/2)
Answer:
the answer is 3
Step-by-step explanation:
(-5x-3)(-5x+3)=(5x)^2 - (3)^2
A difference of squares is the difference of two squared terms.
We have
a^2 - b^2
We can factorize the difference of squared terms like this:
a^2-b^2 = (a+b)(a-b)
We have (-5x-3)(-5x+3)
Lets prove it:
(-5x-3)(-5x+3) = (-5x*-5x)+(-5x*3)+(-3*-5x)+(-3*3)
(-5x-3)(-5x+3) = 25x^2+(-15x)+(15x)+(-9)
(-5x-3)(-5x+3) = 25x^2-15x+15x-9
(-5x-3)(-5x+3) = 25x^2-9
(-5x-3)(-5x+3) = (5x)^2 - (3)^2
