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Gnesinka [82]
2 years ago
5

Cosθ(tanθ + cotθ) = • cscθ • secθ • cos^2θ • 1

Mathematics
2 answers:
arsen [322]2 years ago
6 0

Answer:

ayo i think is ufo trying to communicate hey alien we come in peace

Step-by-step explanation:

forsale [732]2 years ago
6 0

\cos \theta(\tan \theta + \cot \theta)\\\\=\cos \theta \tan \theta  + \cos \theta \cot \theta \\\\=\cos \theta \left (\dfrac{\sin \theta}{\cos \theta} \right)+ \cos \theta \left(\dfrac{\cos \theta}{\sin \theta} \right)\\\\\\=\sin \theta + \dfrac{\cos^2 \theta}{\sin \theta}\\\\=\dfrac{\sin^2 \theta + \cos^2 \theta}{\sin \theta}\\\\=\dfrac 1{\sin \theta}\\\\=\csc \theta

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A taxi driver charges $3 for every kilometre driven, plus $4 per trip.
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3 years ago
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Select the prime number.<br> 30(A)<br> 31(B)<br> 32(C)<br> 33(D)
noname [10]

Answer:

31 as it has only 2 factors which is 1 and 31

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When a breeding group of animals is introduced into a restricted area such as a wildlife reserve, the population can be expected
jasenka [17]

Answer:

A. Initially, there were 12 deer.

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

C. After 15 years, there will be 410 deer.

D. The deer population incresed by 30 specimens.

Step-by-step explanation:

N=\frac{12.36}{0.03+0.55^t}

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N=\frac{12.36}{0.33+0.55^0}

N=\frac{12.36}{0.03+1} =\frac{12.36}{1.03} = 12

A. Initially, there were 12 deer.

B. N(10)=\frac{12.36}{0.03 + 0.55^t} =\frac{12.36}{0.03 + 0.0025}=\frac{12.36}{y}=380

B. <em>N(10)</em> corresponds to the amount of deer after 10 years since the herd was introducted on the reserve.

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C. After 15 years, there will be 410 deer.

D. The variation on the amount of deer from the 10th year to the 15th year is given by the next expression:

ΔN=N(15)-N(10)

ΔN=410 deer - 380 deer

ΔN= 30 deer.

D. The deer population incresed by 30 specimens.

8 0
3 years ago
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Adding 80 both sides

5x-80+80=x+80

5x=x+80

Subtracting x both sides

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4x=80

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