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3 years ago

According to rounding rules for addition, the sum of 27.1, 34.538, and 37.68 is ____.

Mathematics

2 answers:

Maru [420]3 years ago

6 0

Answer:

According to rounding rules for addition, the sum of 27.1, 34.538, and 37.68 is

$27.1+34.538+37.68=99.318$

We can give two answers here as its not mentioned how much to be rounded off.

According to the rule, if the digit to be rounded is less than 5, then we do not change the "rounding digit" but change all digits to the right of the "rounding digit" to zero.

So, this sum will be rounded to 100, if it has to be rounded in nearest whole number as per rule.

Otherwise, we can also round up to tenth place to 99.3

If the hundredth place is 5 or greater than 5 then we increase the tenth place by 1.

Here, the hundredth place is 1, so no changes to the tenth place is applied.

stich3 [128]3 years ago

5 0

We are given with three values and is asked in the problem to determine the sum of the three values. Using a calculator, the significant figures should be equal to 5, the answer is equal to 99.318. One can also use manual addition to verify the answer

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2.19x=y

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2 years ago

Rex, Paulo, and Ben are standing on shore watching for dolphins. Paulo sees one surface directly in front of him about a hundred

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$\dfrac{AC}{AB}= \dfrac{AD}{AC}$ .

3. Knowing lengths you could state that $\dfrac{b}{c}= \dfrac{e}{b}$ .

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$\dfrac{BC}{BD}= \dfrac{AB}{BC}$ .

7. Knowing lengths you could state that $\dfrac{a}{d}= \dfrac{c}{a}$ .

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3 years ago

Read 2 more answers

Harmonic mean if a number h such that (h-a)/(b-h)=a/b Prove h is H(a,b) iff satisfies either relation a. (1/a)-(1/h) = (1/h) - (

Fudgin [204]

A.

$\displaystyle\frac1a-\frac1h=\frac1h-\frac1b$
$\implies\displaystyle\frac{h-a}{ah}=\frac{b-h}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac{ah}{bh}$
$\implies\displaystyle\frac{h-a}{b-h}=\frac ab$

b.

$\displaystyle h=\frac{2ab}{a+b}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{\frac{2ab}{a+b}-a}{b-\frac{2ab}{a+b}}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{2ab-a(a+b)}{b(a+b)-2ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{ab-a^2}{b^2-ab}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac{a(b-a)}{b(b-a)}$
$\displaystyle\implies\frac{h-a}{b-h}=\frac ab$

The other direction can be proved by following the manipulations in the reverse order.

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2 years ago

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2 years ago

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Please help!!! Thank you!!!

Reptile [31]

To find the total area of this figure, it would be easiest to find the area of the left part (rectangle) and then find the area of the right part (triangle), and then add the two area values together.

First, we will find the area of the rectangle, using the formula A = lw, where l is the length of the rectangle and w is the width of the rectangle.
The length of the rectangle is 13 cm and the width is 9 cm. If we substitute in these values into our equation, we get:
A = (13cm)(9cm)
A= 117 cm^2

Next, let’s find the area of the triangle, using the formula A=(1/2)bh, where b is the base of the triangle and h is the height.
The base of the triangle is 11 cm and the height of the triangle is 5 cm (found by subtracting 13-8 as seen in the figure). If we substitute in these values and simplify, we get:
A=1/2(11cm)(5cm)
A=1/2(55cm^2)
A=27.5 cm^2.

When we add together the area of the rectangle with the area of the triangle, we will get the total area of the figure.

117 cm^2 + 27.5 cm^2 = 144.5 cm^2
Your answer is 144.5 cm^2 or the first option.

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2 years ago