805 x 10
anything multiplied by ten adds a 0 before the decimal place or moves the number from past the decimal place forward--
answer is 8050
if you had 2400.23 x 10 you would move the two into the ones place
24002.3
Answer:

Step-by-step explanation:
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![\dfrac{8}{5} - \left[-\dfrac{2}{3}\right]](https://tex.z-dn.net/?f=%5Cdfrac%7B8%7D%7B5%7D%20-%20%5Cleft%5B-%5Cdfrac%7B2%7D%7B3%7D%5Cright%5D)




Answer:
y = 1
Step-by-step explanation:
Rearrange:
Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :
6-(2*(y+2))=0
Step by step solution :
Equation at the end of step 1 :
6 - 2 • (y + 2) = 0
Pulling out like terms :
3.1 Pull out like factors :
2 - 2y = -2 • (y - 1)
Equation at the end of step 3 :
-2 • (y - 1) = 0
Equations which are never true :
4.1 Solve : -2 = 0
This equation has no solution.
A a non-zero constant never equals zero.
Solving a Single Variable Equation :
4.2 Solve : y-1 = 0
Add 1 to both sides of the equation :
y = 1
One solution was found :
y = 1
Processing ends successfully
plz mark me as brainliest :)
Answer:
"the sum of the cube of 6x and 2"
Step-by-step explanation:
We see that only the expression of 6x is being cubed, not the entire expression of (6x)³ + 2.
The first blank must apply to both these terms 6x and 2, so the word can't be cubed. Instead, because we're finding the sum of these two, the word should be "sum".
The second blank should apply to only the 6x because we've already described the relationship of 6x and 2. So, since we are cubing 6x, the word here should be "cube".
The final sentence should read:
"the sum of the cube of 6x and 2"
Answer: i think its just 1
Step-by-step explanation: