Answer: trachea bronchi bronchioles alveoli
Explanation:
Answer:
a) We need to find p(x<68.15)
Standardize x to z, we have, z = (68.15-μ)/σ
=(68.15-57)/8.1
=1.38
Reading from standard normal tables,
p(z<1.38) =0.9162.
b) We need to find p(x>54.4)
Standardize x to z, we have, z = (54.4-μ)/σ
=(54.4-57)/8.1
=-0.32
Reading from standard normal tables,
p(z>-0.32) = 0.6255
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Using the hypergeometric distribution, it is found that the probability is 0.845 = 84.5%.
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- The patients are chosen from the sample without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by:

The parameters are:
- x is the number of successes.
- N is the size of the population.
- n is the size of the sample.
- k is the total number of desired outcomes.
Combination formula:
is the number of different combinations of x objects from a set of n elements, given as:

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- 56074 patients, thus

- Sample of 40, thus,

- 235 left against medical advice, thus,
.
The probability that none left against medical advice is P(X = 0), so:


The probability is 0.845 = 84.5%.
A similar problem is given at brainly.com/question/24008577