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monitta
2 years ago
9

can someone please help me with this one? I’ve been stuck on it for ages! Tysm if you do!! I appreciate it!

Mathematics
1 answer:
Charra [1.4K]2 years ago
4 0

Answer:

50

110

90

=250

Step-by-step explanation: 90+50+110

I HOPE THIS HELPS

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Yall please help meee
madam [21]

Answer-

x=0;y=3

x=1;y=-1

x=2;y=-5

x=3;y=-9

7 0
3 years ago
Tracy McKinney is a disc jockey at radio station WMMM. Her annual salary is $52,750. What is her monthly salary?
attashe74 [19]
Okay, so since her annual salary is <span>$52,750 (the amount she gets a year, all twelve months combined) you're trying to find how much she gets monthly. That would mean we would have to divide her annual salary by 12 to find her monthly salary.

</span>$52,750 ÷ 12 = 4,395.8333333333333
<span>
And since that's a (bothersome) repeating decimal, we're going to have to round it. Once rounded, you would get $</span>4,395.83. That is her monthly salary.
5 0
3 years ago
HELP QUICKLY what is the equation of the line through (-10,-7) and (-5,-9)
hichkok12 [17]
This is your answer

7 0
2 years ago
Read 2 more answers
Last year at a certain high school, there were 100 boys on the honor roll and 84 girls on the honor roll. This year, the number
-BARSIC- [3]

Answer:

I Think the honor of total students is 50%

Step-by-step explanation:

25 +17=45

Round 45 to the nearest tenth and you get 50

6 0
3 years ago
Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)
Mnenie [13.5K]
One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
(x-h)^2+(y-k)^2=r^2
the center is (h,k) and the radius is r

and the distance formula is
distance between (x_1,y_1) and (x_2,y_2) is
D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}


r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle


so
(x+2)^2+(y-3)^2=18
(x-(-2))^2+(y-3)^2=(\sqrt{18})^2
(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2

the radius is 3\sqrt{2}
center is (-2,3)

find distance between (8,4) and (-2,3)

D=\sqrt{(8-(-2))^2+(4-3)^2}
D=\sqrt{(8+2)^2+(1)^2}
D=\sqrt{10^2+1}
D=\sqrt{100+1}
D=\sqrt{101}




r=3\sqrt{2}≈4.2
D=\sqrt{101}≈10.04

do r<D

(8,4) is outside the circle

6 0
3 years ago
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