The answer is less since its negative. Hope this helps!!!!!!
<h3>
<u>Explanation</u></h3>
![\begin{cases}h = - \frac{b}{2a} \\ k = \frac{4ac - {b}^{2} }{2a} \end{cases}](https://tex.z-dn.net/?f=%20%5Cbegin%7Bcases%7Dh%20%3D%20%20-%20%20%5Cfrac%7Bb%7D%7B2a%7D%20%20%5C%5C%20k%20%3D%20%20%5Cfrac%7B4ac%20-%20%20%7Bb%7D%5E%7B2%7D%20%7D%7B2a%7D%20%20%5Cend%7Bcases%7D)
The vertex of Parabola is the maximum/minimum point depending on the value of a.
<u>h-value</u>
![h = - \frac{5}{2(1)} \\ h = - \frac{5}{2}](https://tex.z-dn.net/?f=h%20%3D%20%20-%20%20%5Cfrac%7B5%7D%7B2%281%29%7D%20%20%5C%5C%20h%20%3D%20%20-%20%20%5Cfrac%7B5%7D%7B2%7D%20)
<u>k-value</u>
![k = \frac{4(1)( - 6) - {(5)}^{2} }{4(1)} \\ k = \frac{ - 24 - 25}{4} \\ k = \frac{ - 49}{4} \\ k = - \frac{49}{4}](https://tex.z-dn.net/?f=k%20%3D%20%20%5Cfrac%7B4%281%29%28%20-%206%29%20-%20%20%7B%285%29%7D%5E%7B2%7D%20%7D%7B4%281%29%7D%20%20%5C%5C%20k%20%3D%20%20%5Cfrac%7B%20-%2024%20-%2025%7D%7B4%7D%20%20%5C%5C%20k%20%3D%20%20%5Cfrac%7B%20-%2049%7D%7B4%7D%20%20%5C%5C%20k%20%3D%20%20-%20%20%5Cfrac%7B49%7D%7B4%7D%20)
The minimum value is the value of k. Therefore the minimum value is - 49/4 at x = -5/2.
This is Calculus method. We simply differentiate the function then substitute y' = 0.
![f'(x) = 2 {x}^{2 - 1} + {5x}^{1 - 1} - 0 \\ f'(x) = 2x + 5](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%202%20%7Bx%7D%5E%7B2%20-%201%7D%20%20%2B%20%20%7B5x%7D%5E%7B1%20-%201%7D%20%20-%200%20%5C%5C%20f%27%28x%29%20%3D%202x%20%2B%205)
Substitute f'(x) = 0
![0 = 2x + 5 \\ - 5 = 2x \\ - \frac{5}{2} = x](https://tex.z-dn.net/?f=0%20%3D%202x%20%2B%205%20%5C%5C%20%20-%205%20%3D%202x%20%5C%5C%20%20%20-%20%20%5Cfrac%7B5%7D%7B2%7D%20%20%3D%20x)
Substitute x = -5/2 in the original equation.
![f(x) = {( - \frac{5}{2} )}^{2} + 5( - \frac{5}{2} ) - 6 \\ f(x) = \frac{25}{4} - \frac{25}{2} - 6 \\ f(x) = \frac{25}{4} - \frac{50}{4} - \frac{24}{4} \\ f(x) = \frac{25}{4} - \frac{74}{4} \\ f(x) = - \frac{49}{4}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20%20%7B%28%20-%20%20%5Cfrac%7B5%7D%7B2%7D%20%29%7D%5E%7B2%7D%20%20%2B%205%28%20-%20%20%20%5Cfrac%7B5%7D%7B2%7D%20%29%20-%206%20%5C%5C%20f%28x%29%20%3D%20%20%5Cfrac%7B25%7D%7B4%7D%20%20-%20%20%5Cfrac%7B25%7D%7B2%7D%20%20-%206%20%5C%5C%20f%28x%29%20%3D%20%20%5Cfrac%7B25%7D%7B4%7D%20%20-%20%20%5Cfrac%7B50%7D%7B4%7D%20%20-%20%20%5Cfrac%7B24%7D%7B4%7D%20%20%5C%5C%20f%28x%29%20%3D%20%20%5Cfrac%7B25%7D%7B4%7D%20%20-%20%20%5Cfrac%7B74%7D%7B4%7D%20%20%5C%5C%20f%28x%29%20%3D%20-%20%20%20%5Cfrac%7B49%7D%7B4%7D%20)
<h3>
<u>Answer</u><u /></h3>
<u>
</u>
Answer:
The answer is "(5, -6)"
Step-by-step explanation:
Given:
The Pre-image line at point B is: (3, 4)
Solution:
![\ rx-axis \circ \ T2,2 (3,4) \\\\\Rightarrow \ rx-axis \ ( T2,2 (3,4) )\\\\ \Rightarrow \ rx-axis ( 5,6 ) \\\\ \Rightarrow (5, -6)\\](https://tex.z-dn.net/?f=%5C%20rx-axis%20%5Ccirc%20%5C%20%20T2%2C2%20%283%2C4%29%20%5C%5C%5C%5C%5CRightarrow%20%20%5C%20rx-axis%20%5C%20%28%20T2%2C2%20%283%2C4%29%20%29%5C%5C%5C%5C%20%5CRightarrow%20%5C%20rx-axis%20%28%205%2C6%20%20%29%20%5C%5C%5C%5C%20%5CRightarrow%20%20%285%2C%20-6%29%5C%5C)
The coordinates of B point is (5,-6).
I assume what you mean by this question is an equation like this:
1 + 2 x 3 + 4
Or,
3 x 4 + 6 /div 5
--
What you'd do:
1+2 x 3+4 First, add either 1+2 or 3+4 which is 3 & 7. then, youd multiply your answers as, 3 x 7 which is, 21.
--
Please ask if you have any questions