Here we can first find the area of yard and then subtract the area of vegetable garden to get the required area.
The formula to find area is given by:
![A = l* w](https://tex.z-dn.net/?f=%20A%20%3D%20l%2A%20w%20)
Now we find area of yard:
length is 25 ft and width is 15 ft.
![A = 25 * 15](https://tex.z-dn.net/?f=%20A%20%3D%2025%20%2A%2015%20)
Area of yard = 375 ft²
Area of vegetable garden:
length = 8ft and width =8ft
So the vegetable garden is a square.
Area = 8*8
Area of vegetable garden =64 ft²
Area of backyard to be laid with grass = Area of yard-Area of vegetable garden
Area required = 375 -64 = 311 ft²
Answer : The area of backyard in which grass is to be laid is 311 square feet.
Answer:
Step-by-step explanation:
Associative property
Answer:
the total number who liked pop or rock music ik the age geoup is 186
GuuUuuuuUuuurl we can’t see graphs sos
Answer:
![\bigl(\frac{3}{2},-5\bigr)](https://tex.z-dn.net/?f=%5Cbigl%28%5Cfrac%7B3%7D%7B2%7D%2C-5%5Cbigr%29)
or in decimal form
![(1.5,-5)](https://tex.z-dn.net/?f=%281.5%2C-5%29)
Step-by-step explanation:
The midpoint of the line with endpoints
and
is
. just take the average between the points
so given the points (1,0) and (2,-10)
![x_1=1](https://tex.z-dn.net/?f=x_1%3D1)
![y_1=0](https://tex.z-dn.net/?f=y_1%3D0)
![x_2=2](https://tex.z-dn.net/?f=x_2%3D2)
![y_2=-10](https://tex.z-dn.net/?f=y_2%3D-10)
the midpoint is found as follows:
![\bigl(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}\bigr)](https://tex.z-dn.net/?f=%5Cbigl%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%5Cbigr%29)
![\bigl(\frac{1+2}{2},\frac{0-10}{2}\bigr)](https://tex.z-dn.net/?f=%5Cbigl%28%5Cfrac%7B1%2B2%7D%7B2%7D%2C%5Cfrac%7B0-10%7D%7B2%7D%5Cbigr%29)
![\bigl(\frac{3}{2},\frac{-10}{2}\bigr)](https://tex.z-dn.net/?f=%5Cbigl%28%5Cfrac%7B3%7D%7B2%7D%2C%5Cfrac%7B-10%7D%7B2%7D%5Cbigr%29)
![\bigl(\frac{3}{2},-5\bigr)](https://tex.z-dn.net/?f=%5Cbigl%28%5Cfrac%7B3%7D%7B2%7D%2C-5%5Cbigr%29)
or in decimal form
![(1.5,-5)](https://tex.z-dn.net/?f=%281.5%2C-5%29)