1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kolezko [41]
2 years ago
12

Find the inverse of f(x) = x^2 - 7

Mathematics
1 answer:
blondinia [14]2 years ago
3 0

Answer:

y =  ±  sqrt(x+7)

Step-by-step explanation:

y = x^2 -7        solve for 'x'     .... add 7 to both sides

y+7  = x^2         sqrt both sides

+- sqrt(y+7)  = x        switch 'x' and 'y'

y = +- sqrt(x+7)

You might be interested in
....................................
Ronch [10]

Answer:

................................

Step-by-step explanation:

.................................................................

7 0
3 years ago
Read 2 more answers
A ladder leans against the side of a house. The angle of elevation of the ladder is 70 when the bottom of the ladder is 16ft fro
makkiz [27]

46.78

Step-by-step explanation:

you divide 16 by the cos of 70 and it turns out to be 46.78

3 0
3 years ago
Someone answer this random question
gayaneshka [121]

Answer:

hmmmmm... thats a tough one

its probably ur mom

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
If a polynomial has one root in the form a + the square root of B it has a second root in the form of a _ square root of b.
trapecia [35]
I THOUGHT i ANSWERED THAT?
SEE FASCTOR THEOREM :aNSWER IS MINUS (A -  <span>√ B)</span>
6 0
3 years ago
Read 2 more answers
Given the function f(x)= 14x^2 + 5x - 1 answer the question if you could change the 14 to any other number, but the rest has to
polet [3.4K]
This is a polynomial of degree 2, and remember that complex roots always come in pairs; therefore, in a second degree polynomial you can only have 0 real roots and 2 complex roots, or 2 real roots and 0 complex roots. There is no way you can have 1 real root and 1 complex root because, as stated before, complex (non-real) roots always come in pairs; so the only way of having 1 real root is dumping the polynomial of degree 2 (14 x^{2}) by changing the 14 to 0. That way we'll left with f(x)=5x-1 which only has one real root:
0=5x-1
5x=1
x= \frac{1}{5}

7 0
3 years ago
Read 2 more answers
Other questions:
  • How do you turn 26.2 into a fraction
    11·2 answers
  • The weight of water 62 1/2 lb per cubic foot. What is the weight of 29 1/8 cubic feet of water? Simplify the answer using whole
    7·1 answer
  • Simplify the given equation.
    5·1 answer
  • Solve the equation there’s no solution right no solution <br><br> J/5+1=-4
    9·1 answer
  • What is 75 1/3% as a fraction in simplest form
    11·2 answers
  • Jennifer earns $17.35 per hour at her job. She works 6 hours per day, 5 days per week. What is Jennifer’s gross income for a 2 w
    13·1 answer
  • Three boys and six girls are being seated in a row of nine chairs on a stage which are numbered from left to right. How many sea
    15·1 answer
  • What would I get if I had six tenths and one ninth
    7·1 answer
  • This is Adele's solution for the equation x^2 + 8x - 9 = 0 Step 1 x^2 + 8x - 9 = 0 Step 2 x^2 + 8x = 9 Step 3 ( x + 4 )^2 = 25 S
    11·2 answers
  • Plzz help geometry
    8·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!