Question

Select the correct answer.

Answer 1

Answer:

Option D

Step-by-step explanation:

Use Factoring Methods

$4x^3-8x^2-9x+18$

put bracket around each 2 terms as such $(4x^3-8x^2)+(-9x+18)$

And then factor each respective bracket. We'll start with the first one

$(4x^3-8x^2) = 4x^2(x-2)$

Then do the other, and try to get similar brackets as the first

$(-9x+18)=-9(x-2)$

Since they are both simiar, the equation is now: $(4x^2-9)(x-2)$

Now factor the first bracket again for final result

$4x^2-9=(2x-3)(2x+3)$

Ans when you put it all together, you get: $(2x-3)(2x+3)(x-2)$

Correct answer is option D