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3 years ago

32) 48,504 ÷ 16

Mathematics

1 answer:

Nataly [62]3 years ago

3 0

32)3031.5 odd

33)even 22,699

34)even 2,806,046,958

35)even 109946958

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Which of the graphs best represents a system of equations that has no solution?

Lesechka [4]

When the lines are parallel then there is no solution to the system of equations.
This happens because the intersection is the solution. And when there is no intersection then there is no solution.

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3 years ago

HELP ME PLEASE !!!!!!!!!

Kay [80]

Answer: 33 333,33 per month or 400 000 per year

Step-by-step explanation:

You need 48 000 + 0.035X = 62 000

So ( 62 000 - 48 000 ) / 0.035 = X

Then you can divide X per 12 (months in a year)

And you have your answer per month .

So 33 333,33 total sale per month to have at least as high as the average pay

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A game involves spining this spinner. what is the probality that the pointer will land on g?

Doss [256]

There's a 1 in 7 chance it will land on G.

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3 years ago

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Helpppp pleaseeee!!!!

dimaraw [331]

I could be wrong but I think you solve for y then graph it then find where the lines intersect. You’re using ed puzzle though so just rewatch the part of the video and you’ll get the answer.

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3 years ago

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Solving Quadratic Equations with Complex SolutionsThe discriminant: D=b^2-4acQuestion:5x^2-2x+1=0

fomenos

• The value of the discriminant ,D= -16

• The solution to the quadratic equation is

$x=\frac{1+2i}{5}\text{ or }\frac{1-2i}{5}$

Step - by - Step Explanation

What to find?

• The discriminant d= b² - 4ac

• The solution to the quadratic equation.

Given:

5x² - 2x + 1=0

Comparing the given equation with the general form of the quadratic equation ax² + bx + c=0

a=5 b=-2 and c=1

Uisng the quadratic formula to solve;

$x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

The discriminant D=b² - 4ac

Substitute the values into the discriminant formula and simplify.

D = (-2)² - 4(5)(1)

D = 4 - 20

D = -16

We can now proceed to find the solution of the quadratic equation by substituting into the quadratic formula;

$x=\frac{-(-2)\pm\sqrt[]{-16}}{2(5)}$

Note that:

√-1 = i

$x=\frac{2\pm\sqrt[]{16\times-1}}{10}$

$x=\frac{2\pm\sqrt[]{16}\times\sqrt[]{-1}}{10}$ $x=\frac{2\pm4i}{10}$ $x=\frac{2}{10}\pm\frac{4i}{10}$ $x=\frac{1}{5}\pm\frac{2}{5}i$ $x=\frac{1\pm2i}{5}$

That is;

$\text{Either x=}\frac{1+2i}{5}\text{ or x=}\frac{1-2i}{5}$

7 0

1 year ago