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Fofino [41]
2 years ago
14

Scott is playing a game in which he Rolls a number cube with faces number one through 1-6 spins the spinner shown below one time

each how many unique combinations were the number on The cube is greater than 2 and the number on the spinner is less than 9 are possible

Mathematics
1 answer:
SashulF [63]2 years ago
7 0

Answer:

Possible Outcomes

2 7

2 9

4 7

4 9

6 7

6 9

Step-by-step explanation:

for starters,we know that the dice has 6 numbers, but since we want it to only show even numbers, we can eliminate 1,3,5 from the dice.

For the spinner, we know that there are four numbers on it, but we only want it to show odd numbers, so eliminate all the even numbers on the spinner. Therefore we're left with 7 and 9.

Since we want every possible outcome, we link each available number on the dice to a number available on the spinner, therefore we can group them into subsets.

eg: We start with 2 on the dice, then we will pair it with 7. So, (2,7)

    Then, we pair 2 with the final and only number left on the spinner, which is 9. Hence, (2,9)

Do this step so on so forth, until every even number on the dice has two pairs with the spinner.

You'll get: (2,7)   (2,9)  (4,7)  (4,9)  (6,7)  (6,9)

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