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4 years ago

What is the answer for 1 - ( -3)

Mathematics

2 answers:

Salsk061 [2.6K]4 years ago

8 0

answer is 4 because negative symbols are going to be positive.

mel-nik [20]4 years ago

7 0

Answer:1-(-3)=1+3=4.

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The gray area is the sidewalk. The area of the sidewalk is ___________ square units.

9966 [12]

72 square units.
10 x 12= 120
6 x 8 = 48
120 - 48 = 72.
Hope this helps. :)

6 0

3 years ago

1 dozen roses for $29.75 how much does one rose cost

rewona [7]

Answer:

$2.48

Step-by-step explanation:

29.75/12 =2.479

7 0

2 years ago

A store owner was buying uniforms for his employees. If each of his stores needed 79 uniforms and he had 64 stores which express

seraphim [82]

Answer:

C) The total number of about uniforms needed is 60 x 80 uniforms.

Step-by-step explanation:

The Number of total stores the owner has = 64 stores

The number of employees uniform needed in 1 store = 79 uniforms

Now, 64 is Rounded off to about 60.

and 79 is Rounded off to about 80.

⇒ The total number of uniforms in 60 stores = 60 x ( uniform in 1 store)

= 60 x (80 uniforms)

or, the expression of total uniforms needed = 60 x (80 uniforms)

Hence, the total number of about uniforms needed is 60 x 80 uniforms.

4 0

3 years ago

A manufacturer of shipping boxes has a box shaped like a cube. The side length is

Tatiana [17]

The volume of a cube with side length equal to x, is $V= x^{3}$ ,

thus, the volume of a cube shaped box, whose side length is (5a+4b) is :

$V= (5a+4b)^{3}$ ,

The volume is already expressed in terms of a and b, but we can expand the expression $(5a+4b)^{3}$ , as follows:

$(5a+4b)^{3} =(5a+4b)(5a+4b)^{2}= (5a+4b)[ (5a)^{2}+2(5a)(4b)+ (4b)^{2}]$

$=(5a+4b)[ 25a^{2}+40ab+ 16b^{2}]$

$=(5a)[ 25a^{2}+40ab+ 16b^{2}]+(4b)[ 25a^{2}+40ab+ 16b^{2}]$

$=125a^{3}+200a^{2} b+ 80ab^{2}+100a^{2}b+160ab^{2} + 64b^{3}$

$125a^{3}+300a^{2} b+240ab^{2} + 64b^{3}$

Answer:

$V= (5a+4b)^{3}$ ,

or

$125a^{3}+300a^{2} b+240ab^{2} + 64b^{3}$

7 0

3 years ago

Find x in this trigonometry question

IRINA_888 [86]

$\tan 61=\dfrac{y}{10}\\
y=10\tan 61\\\\
\cos 55=\dfrac{z}{10 \tan 61}\\
z=10\tan 61\cos 55\\\\
\sin x=\dfrac{10\tan 61\cos 55}{12}\\
\sin x\approx\dfrac{10\cdot1.8\cdot0.57}{12}\\
\sin x\approx0.855\\
x\approx58.76^{\circ}$

8 0

3 years ago