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Ksenya-84 [330]
2 years ago
8

Please help me . With explanation:)

Mathematics
1 answer:
zhuklara [117]2 years ago
6 0
<h3>Answer:  35</h3>

===============================================================

Explanation:

To start off, we'll find the circumference of the full circle. We'll ignore the black and yellow sectors.

C = 2*pi*r

C = 2*pi*7

C = 14pi

This is the exact distance around the full circle in terms of pi

However, we don't want the the full circular perimeter. Instead, we only want the portions that are along the black sectors. The yellow sectors have central angle 24 degrees each. This takes up 3*24 = 72 degrees overall because the three regions have equal area and equal central angle.

Subtract that from 360:

360-72 = 288

The yellow regions take up 72 degrees while the remaining black sectors take up a combined 288 degrees.

------------------------------

Why is 288 useful? Because it helps set up the fraction 288/360 to represent the portion of the perimeter that we care about.

(288/360)*14pi = 35.1858 mm approximately

This rounds to 35 mm

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B=3 V/h<br> I’m supposed to solve the question for V.
FromTheMoon [43]
Answer:
V=Bh/3

Explanation:
B=3V/h
1) Multiply h on both sides.
Bh=3v
2) Divide both sides by 3
Bh/3=V
6 0
2 years ago
Thank u so much much appreciated
attashe74 [19]

Answer:

A

Step-by-step explanation:

The definition of a parrelelogram is "a four-sided plane rectilinear figure with opposite sides parallel". Since you already know that EH and Fg are equal because of the black ticks on them. Now you only need to find out wheter or not  EF≅HG to meet the criteria of a parrelologram.

7 0
3 years ago
Problems 2.21, 2.22, 2.23
RoseWind [281]

Statements can be proved by contrapositive, contradiction or by induction.

  • <em>2.21 and 2.23 are proved by contrapositive</em>
  • <em>2.22 is proved by induction</em>

<u />

<u />

<u>2.21: If </u>n^3<u> is even, then n is even (By contrapositive)</u>

The contrapositive of the above statement is that:

<em>If n is odd, then  </em>n^3<em> is odd</em>

Represent the value of n as:

n = 2k + 1, where k \ge 0

Take the cube of both sides

n^3 = (2k + 1)^3

Expand

n^3 = 8k^3 + 6k^2 + 6k + 1

Group

n^3 =[ 8k^3 + 6k^2 + 6k] + 1

Factor out 2

n^3 =2[4k^3 + 3k^2 + 3k] + 1

Assume w is an integer; where:

w =4k^3 + 3k^2 + 3k

So, we have:

n^3 =2w + 1

The constant term (i.e. 1) means that n^3 is odd.

Hence, the statement has been proved by contrapositive.

<em>i.e. If n is odd, then  </em>n^3<em> is odd</em>

<u />

<u>2.22  </u>3n + 4<u> is even, if and only if n is even</u>

We have: 3n + 4<u />

<u />

Assume that: n = 2k + 2 for k \ge 0

So, we have:

3n + 4 = 3(2k + 2) + 4

Open bracket

3n + 4 = 6k + 6 + 4

3n + 4 = 6k + 10

Factorize

3n + 4 = 2(3k + 5)

The factor of 2 means that 3n + 4 is even.

<em>Hence, </em>3n + 4<em> is even, if and only if n is even </em>

<em />

<u />

<u>2.22: </u>s \ne -1<u> and </u>t \ne -1<u>, then </u>s + t + st \ne -1<u />

To do this, we prove by contrapositive.

The contrapositive of the above statement is:

If s = -1 and t=-1, then s + t + st = -1

We have:

s + t + st = -1

Substitute the values of s and t in: s + t + st = -1

-1 -1 -1 \times -1 = -1

-1 -1 + 1 = -1

-1 = -1

Hence, by contrapositive:

If s = -1 and t=-1, then s + t + st = -1

Read more about proofs  at:

brainly.com/question/19643658

7 0
3 years ago
Is 3x+2y=8 a quadratic equation?
Ierofanga [76]

Answer:

No.

Step-by-step explanation:

No, it is a linear equation.  There are no exponents on the x or y variables.

7 0
2 years ago
Does anyone know how to do this?? Help please!!!!
Doss [256]

Answer:

When we have a rational function like:

r(x) = \frac{x + 1}{x^2 + 3}

The domain will be the set of all real numbers, such that the denominator is different than zero.

So the first step is to find the values of x such that the denominator (x^2 + 3) is equal to zero.

Then we need to solve:

x^2 + 3 = 0

x^2 = -3

x = √(-3)

This is the square root of a negative number, then this is a complex number.

This means that there is no real number such that x^2 + 3 is equal to zero, then if x can only be a real number, we will never have the denominator equal to zero, so the domain will be the set of all real numbers.

D: x ∈ R.

b) we want to find two different numbers x such that:

r(x) = 1/4

Then we need to solve:

\frac{1}{4} = \frac{x + 1}{x^2 + 3}

We can multiply both sides by (x^2 + 3)

\frac{1}{4}*(x^2 + 3) = \frac{x + 1}{x^2 + 3}*(x^2 + 3)

\frac{x^2 + 3}{4} = x + 1

Now we can multiply both sides by 4:

\frac{x^2 + 3}{4}*4 = (x + 1)*4

x^2 + 3 = 4*x + 4

Now we only need to solve the quadratic equation:

x^2 + 3 - 4*x - 4 = 0

x^2 - 4*x - 1 = 0

We can use the Bhaskara's formula to solve this, remember that for an equation like:

a*x^2 + b*x + c = 0

the solutions are:

x = \frac{-b +- \sqrt{b^2 - 4*a*c} }{2*a}

here we have:

a = 1

b = -4

c = -1

Then in this case the solutions are:

x = \frac{-(-4) +- \sqrt{(-4)^2 - 4*1*(-1)} }{2*(1)} = \frac{4 +- 4.47}{2}

x = (4 + 4.47)/2 = 4.235

x = (4 - 4.47)/2 = -0.235

5 0
3 years ago
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