They both have 4 congruent sides and angles.
We are given coordinates of the triangle: A(2,2), B(7,1) and C(8,-4).
We need to rotated 90° counterclockwise about the origin.
In order to find the new coordinates of rotatation 90°counterclockwise about the origin, we can apply rule (h, k) ---> (-k,h).
Where (h,k) are the coordinates of original image on axes and (-k,h) are the coordinates of rotated image.
In resulting coordinates of the image first swap the x and y coordinates of the original image and then make the sign opposite of each x-coordinate.
On applying rule (h, k) ---> (-k,h), we get
A(2,2) --> A'(-2,2)
B(7,1) --> B'(-1,7)
C(8,-4) --> C'(4,8)
Every angle of a square equals 90 degrees.
2x - 4 = 90 3y + 6 = 90
2x = 90 + 4 3y = 90 - 6
2x = 94 3y = 84
x = 94/2 y = 84/3
x = 47 y = 28
so x = 47 and y = 28
Answer:
a=-8 b=2
Step-by-step explanation:
x^2+6x-16
x^2+(8-2)x-16=0
x^2+8x-2x-16=0
X(X+8)-2(X+8)=0
(X+8)(x-2)=0
Compare with (X+a)(X+b)
Where we get a=-8 b=2