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3 years ago

Write and solve a real-world word problem in which there are 3 tables for every 8 chairs.

Mathematics

1 answer:

alekssr [168]3 years ago

4 0

That means there are 24 chairs. What you would do is multiply 8 by 3 which gives you 24.

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James, a real estate appraiser is looking at homes in the 78681 zip code. He takes a random sample of 42 homes form the Austin M

vazorg [7]

Answer:

80% confidence interval for the proportion of homes that are "eclectic" is [0.59 , 0.78].

Step-by-step explanation:

We are given that James takes a random sample of 42 homes form the Austin MLS (that's where Realtors go for information) and finds that 29 of them are listed as "eclectic" style.

Firstly, the pivotal quantity for 80% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of homes that are "eclectic" = $\frac{29}{42}$ = 0.69

n = sample of homes = 42

$\mu$ = population proportion of homes that are "eclectic"

Here for constructing 80% confidence interval we have used One-sample z proportion statistics.

So, 80% confidence interval for the population proportion, p is ;

P(-1.282 < N(0,1) < 1.282) = 0.80 {As the critical value of z at 10% level

of significance are -1.282 & 1.282}

P(-1.282 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 1.282) = 0.80

P( $-1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.80

P( $\hat p-1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.80

80% confidence interval for p = [ $\hat p-1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+1.282 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.69-1.282 \times {\sqrt{\frac{0.69(1-0.69)}{42} } }$ , $0.69+1.282 \times {\sqrt{\frac{0.69(1-0.69)}{42} } }$ ]

= [0.59 , 0.78]

Therefore, 80% confidence interval for the proportion of homes that are "eclectic" is [0.59 , 0.78].

7 0

3 years ago

Figure ABCD has vertices A(−4, 1), B(2, 1), C(2, −5), and D(−4, −3). What is the area of Figure ABCD?

Juliette [100K]

Check the picture below.

so, notice, the composite is just a 4x6 rectangle, and a triangle whose base is 6 and altitude is 2. So, we can simply get the area of each figure and sum them up.

$\bf \stackrel{\textit{area of rectangle}}{(4\cdot 6)}~~~~+~~~~\stackrel{\textit{area of triangle}}{\cfrac{1}{2}(6)(2)}$

5 0

3 years ago

The length of a rectangle is 1 ft more than twice the width, and the area of the rectangle is 45 ft2 . find the dimensions of th

zhuklara [117]

Width is 4.5 ft. length is 10 ft.

3 0

4 years ago

How did you determine the number of cups needed to make a stack 50 cm in height?

Katena32 [7]

Answer:

the number of cups is kept within other till the cups reach reach 50cm

x=number of cups

y= height of the cups when placed on each other

so the equation would be ; x + y=50

Step-by-step explanation:

mark brainliest

6 0

3 years ago

Polly has a very rain number of dollar bills in her purse and no change.She spends half the money on a scarf and gives $1dollar

miss Akunina [59]

Answer:$26

Step-by-step explanation:you do the problem in reverse adding when it says spends and multiplying when it says half. she has $1 dollar left if you work in reverse you then add $3 and get $4. then add $2 and get $6 then multiply that by 2 getting $12. you then add $1 and get $13 then the last step is multiplying and you get $26. hope this helps

3 0

4 years ago