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kogti [31]
3 years ago
10

What type of bus does PCI use?

Computers and Technology
1 answer:
Vera_Pavlovna [14]3 years ago
8 0

Answer:

PCI uses a 32-bit or 64-bit parallel bus.

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Switches: Select one:
const2013 [10]

Answer:

b. connect two or more network segments that use different data link protocols

Explanation:

A switch is an analog device that allows to interconnect networks, it is possibly one of the devices with a higher level of scalability. It is important to clarify that a Switch does not only provide connectivity with other networks, nor does it provide connectivity with the Internet, for this purpose a router is necessary.  

6 0
3 years ago
Images are available in many formats, such as tif, bmp, gif, jpeg, and ____.
Lerok [7]
<span>Images are available in many formats, such as tif, bmp, gif, jpeg, and png.

</span>Hope that helps.
7 0
3 years ago
Write a program with 2 separate functions which compute the GCD (Greatest Common Denominator) and the LCM (Lowest Common Multipl
Maru [420]

Answer:

The program written in Python is as follows

def GCD(num1, num2):

    small = num1

    if num1 > num2:

         small = num2

    for i in range(1, small+1):

         if((num1 % i == 0) and (num2 % i == 0)):

              gcd = i

    print("The GCD is "+ str(gcd))

def LCM(num1,num2):

    big = num2  

    if num1 > num2:

         big = num1

    while(True):

         if((big % num1 == 0) and (big % num2 == 0)):

              lcm = big

              break

         big = big+1

     print("The LCM is "+ str(lcm))

 print("Enter two numbers: ")

num1 = int(input(": "))

num2 = int(input(": "))

GCD(num1, num2)

LCM(num1, num2)

Explanation:

This line defines the GCD function

def GCD(num1, num2):

This line initializes variable small to num1

    small = num1

This line checks if num2 is less than num1, if yes: num2 is assigned to variable small

<em>     if num1 > num2: </em>

<em>          small = num2 </em>

The following iteration determines the GCD of num1 and num2

<em>     for i in range(1, small+1): </em>

<em>          if((num1 % i == 0) and (num2 % i == 0)): </em>

<em>               gcd = i </em>

This line prints the GCD

    print("The GCD is "+ str(gcd))

   

This line defines the LCM function

def LCM(num1,num2):

This line initializes variable big to num2

    big = num2  

This line checks if num1 is greater than num2, if yes: num1 is assigned to variable big

<em>     if num1 > num2: </em>

<em>          big = num1 </em>

The following iteration continues while the LCM has not been gotten.

    while(True):

This if statement determines the LCM using modulo operator

<em>          if((big % num1 == 0) and (big % num2 == 0)): </em>

<em>               lcm = big </em>

<em>               break </em>

<em>          big = big+1 </em>

This line prints the LCM of the two numbers

     print("The LCM is "+ str(lcm))

The main starts here

This line prompts user for two numbers

print("Enter two numbers: ")

The next two lines get user inputs

num1 = int(input(": "))

num2 = int(input(": "))

This calls the GCD function

GCD(num1, num2)

This calls the LCM function

LCM(num1, num2)

<em></em>

<em>See attachment for more structured program</em>

Download txt
5 0
3 years ago
In what kind of attack can attackers make use of millions of computers under their control in an attack against a single server
rjkz [21]

Answer:

Distributed DOS attacks.

Explanation:

Computers in a network or the network itself is are prone to cyber attacks. A cyber attack is a concept of taking advantage of computer network vulnerabilities, to retrieve information from the target source. An example of these types of security attacks is the denial of service (or DOS) attacks.

The DOS  or the distributed DOS attack prevents users form accessing or requesting a service that they are legitimately allowed, by flooding the target system with superfluous resource request from millions of computers, controlled by the attacker.

8 0
3 years ago
4. Write a program to calculate square root and<br>cube root of an entered number .​
nataly862011 [7]

Answer:

DECLARE SUB SQUARE (N)

CLS

INPUT “ENTER ANY NUMBER”; N

CALL SQUARE(N)

END

SUB SQUARE (N)

S = N ^ 2

PRINT “SQUARE OF NUMBER “; S

END SUB

3 0
3 years ago
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