The first five terms of the sequence are -8, -5/8, 0, 5/64 and 16/125
<h3>Recursive form of a sequence</h3>
Given the nth term of a sequence expressed as:
an= n^2-9/ n^3
Determine the first five terms
If n = 1
a1 = 1^2-9/ 1^3
a1 = -8/1
a1 = -8
If n = 2
a2 = 2^2-9/ 2^3
a2 = -5/8
If n = 3
a3= 3^2-9/ 1^3
a3 = 9-9/3^3
a3 = 0
If n = 4
a4 = 4^2-9/ 4^3
a4= 16-9/64
a4 = 5/64
If n = 5
a5 = 5^2-9/ 1^3
a5 = 25-9/5^3
a5 = 16/125
Hence the first five terms of the sequence are -8, -5/8, 0, 5/64 and 16/125
Learn more on recursive function here: brainly.com/question/489759
#SPJ1
Answer:
y=21
Step-by-step explanation:
y= 9 cos x =3 so y=3 when x=1 on the base level so if x=7 would be x=1 on the base level * 7 then y=3 on the base level * 7 would be y = 21
Answer:
$30
Step-by-step explanation:
3/3 - 1/3 = 2/3
The fraction shows how much she has left.
2/3 = $20
1/3 = $20 ÷ 2 = $10
3/3 = $10 x 3 = $30
Answer:
The number of adult tickets sold was 67, and the number of student tickets sold was 35.
Step-by-step explanation:
Answer:
n=2
Step-by-step explanation:
1/2(6n-30)=3/4(4-8n)
3n-15=3-6n
9n=18
n=2
