Question

What are the first five terms, a1, a2, a3, a4, a5 of the sequence defined by an= n^2-9/ n^3 and how can the sequence be described (please hurry)

Answer 1

The first five terms of the sequence are -8, -5/8, 0, 5/64 and 16/125

Recursive form of a sequence

Given the nth term of a sequence expressed as:

an= n^2-9/ n^3

Determine the first five terms

If n = 1

a1 = 1^2-9/ 1^3

a1 = -8/1

a1 = -8

If n = 2

a2 = 2^2-9/ 2^3

a2 = -5/8

If n = 3

a3= 3^2-9/ 1^3

a3 = 9-9/3^3

a3 = 0

If n = 4

a4 = 4^2-9/ 4^3

a4= 16-9/64

a4 = 5/64

If n = 5

a5 = 5^2-9/ 1^3

a5 = 25-9/5^3

a5 = 16/125

Hence the first five terms of the sequence are -8, -5/8, 0, 5/64 and 16/125

Learn more on recursive function here: brainly.com/question/489759

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