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Alenkasestr [34]
3 years ago
12

How do scientists use differences and similarities to identify life forms? I NEED TO KNOW ASAP

Chemistry
1 answer:
Darina [25.2K]3 years ago
8 0

Hello!

Answer:

They utilize differences and similarities because some things look almost identical but like one or more things are different about another.

Explanation:

Like a lizard, two lizards have the same face, body shape, etc. but the markings are different, that allows scientists to identify the type of lizard the lizards are, because of the difference.

Hope this helps!

-Starr

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Solar core I think... i hope it helps
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Most chemical digestion and nutrient absorption is performed in the __________.
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They are performed in the JEJUNUM
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What is the net charge of a nitrogen atom with 8 electrons
DaniilM [7]

Answer:

– 1

Explanation:

From the question given above, we obtained the following:

Electron = 8

Net charge of nitrogen =.?

Nitrogen has atomic number of 7. This also means that nitrogen has 7 proton because atomic number of an element is the equal to number of protons in the atom of the element.

Thus, we can obtain the net charge of nitrogen with 8 electrons by calculating the difference between the protons and electrons of the nitrogen atom. This can be obtained as follow:

Proton = 7

Electron = 8

Net charge = Proton – Electron

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Net charge = – 1

Therefore, the net charge of the nitrogen atom with 8 electrons is – 1

7 0
3 years ago
Kc for the reaction of hydrogen and iodine to produce hydrogen iodide, H2(g) I2(g) ⇌ 2HI(g) is 54.3 at 430°C. Determine the init
Jlenok [28]

Answer : The initial concentration of HI and concentration of HI at equilibrium is, 0.27 M and 0.386 M  respectively.

Solution :  Given,

Initial concentration of H_2 and I_2 = 0.11 M

Concentration of H_2 and I_2 at equilibrium = 0.052 M

Let the initial concentration of HI be, C

The given equilibrium reaction is,

                          H_2(g)+I_2(g)\rightleftharpoons 2HI(g)

Initially               0.11   0.11            C

At equilibrium  (0.11-x) (0.11-x)   (C+2x)

As we are given that:

Concentration of H_2 and I_2 at equilibrium = 0.052 M  = (0.11-x)

0.11 - x = 0.052

x = 0.11 - 0.052

x = 0.058 M

The expression of K_c will be,

K_c=\frac{[HI]^2}{[H_2][I_2]}

54.3=\frac{(C+2(0.058))^2}{(0.052)\times (0.052)}

By solving the terms, we get:

C = 0.27 M

Thus, initial concentration of HI = C = 0.27 M

Thus, the concentration of HI at equilibrium = (C+2x) = 0.27 + 2(0.058) = 0.386 M

3 0
4 years ago
What is a committee called that is organized whenever the two house of congress diffrent versions of the same bill?
Mashutka [201]
The correct answer is Conference committee.
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