Answer:
Group 2
Explanation:
The force pulling a tree down is the same that brings a skier to the lodge: food and beer. No, just kidding. Gravity. The parachuter in Group three also has gravity as a key force, but the reverse force of the air on the parachute is a key consideration to the problem, as well as to the parachuter. But it comes close.
Answer:
66.4g
Explanation:
Given parameters:
Mass of AgNO₃ = 69.1g
Unknown:
Mass of Ag₂CrO₄
Solution:
2AgNO₃+ Na₂CrO₄ ⟶ Ag₂CrO₄ + 2NaNO₃
The given equation is balanced.
To solve this problem, solve from the known to the unknown;
1. Find the number of moles of AgNO₃;
Number of moles = ![\frac{mass}{molar mass}](https://tex.z-dn.net/?f=%5Cfrac%7Bmass%7D%7Bmolar%20mass%7D)
atomic mass of Ag = 107.9g/mol
N = 14g/mol
O = 16g/mol
Molar mass of AgNO₃ = 107.9 + 14 + 3(16) = 169.9g/mol
Number of moles =
= 0.41moles
2. From the balanced equation;
2 moles of AgNO₃ produced 1 moles of Ag₂CrO₄ ;
0.41 moles of AgNO₃ will produce
= 0.2moles of Ag₂CrO₄
3:
Mass of Ag₂CrO₄ = number of moles x molar mass
Atomic mass of Ag = 107.9g/mol
Cr = 52g/mol
0 = 16g/mol
Molar mass = 2(107.9) + 52 + 4(16) = 331.8g/mol
so, mass of Ag₂CrO₄ = 0.2 x 331.8 = 66.4g
In order to answer this question, we are going to look at the molar ratio between H2O and H2, we can see that by analyzing the numbers in front of the compounds, and we can see that the molar ratio is 2:2, this means that for every 2 moles of water decomposing, we will end up with 2 moles of H2 being produced, therefore the same amount of moles for H2O will be the same amount of moles of H2, which means that if we have 100 moles of H2O being decomposed, we will also have 100 moles of H2 being produced.
Answer:
Thus, when 2.5 mol of oxygen reacted with hydrogen, 2 * 2.5 mol = 5 so its A
The correct answer to this question is this one:
HF (hydrofluoric acid) is a weak acid.
SO4 2- (sulfite ion) is a weak base
F- (fluoride anion) is a very weak base
HSO4 - (hydrogen sulfate) is a weak acid
Conjugate acid of HF = H2F+ (dihydrogen fluoride)
Conjugate base of HF = F- (fluoride)
Conjugate acid of SO4 2- = HSO4- (hydrogen sulfite)
SO4 2- does not have a conjugate base because you can't take away any H+
Conjugate acid of F- = HF (hydrofluoric acid)
F- does not have a conjugate base because you can't take away any H+
Conjugate acid of HSO4- = H2SO4 (sulphuric acid)
Conjugate base of HSO4- = SO4 2- (sulfite)
In very simple words:
Conjugate acid --> you add an H+
Conjugate base --> you take away an H+