Answer:
1.40 moles.
Explanation:
The balanced chemical equation for the reaction of Phosphorus and Oxygen is as follows -
In Part A, the oxygen was taken in excess. So Phosphorus will be the limiting reagent.
Since, 2 moles of is formed by 4 moles of
So, for 1.8 moles of amount of required moles of =
In Part B, the phosphorus was taken in excess so oxygen will be the limiting reagent.
Since, 2 moles of is formed by 5 moles of oxygen
So, for 1.40 moles of moles of required =
Thus as of now we have 3.60 moles of and 3.50 moles of .
As in the reaction of formation of , oxygen is the limiting reagent.
So the moles of formed by the 3.50 moles of oxygen will be
= = 1.40 moles.
Answer:
3.56x10²³ atoms
Explanation:
To solve this question we need first to determine the moles of iron (II) chloride, FeCl₂, using its molar mass. Then, using Avogadro's number we can solve for the number of atoms:
<em>Moles FeCl₂ - Molar mass: 126.751g/mol-</em>
25g FeCl₂ * (1mol / 126.751g) = 0.1972 moles
<em>Number of atoms:</em>
1 mole of FeCl₂ are 6.022x10²³ molecules of FeCl₂, that means 0.1972moles are:
0.1972mol * (6.022x10²³ molecules / 1mol) = 1.188x10²³ molecules of FeCl₂
In 1 molecule of FeCl₂ there are 3 atoms (1 of Fe and 2 of Cl), in 1.188x10²³ molecules of FeCl₂ there are:
1.188x10²³ molecules of FeCl₂ * (3atoms / molecule) =
<h3>3.56x10²³ atoms</h3>
<span>We know that density is equal to mass divided by volum, D=M/V and in this case we have 1 gallon of a solution of sulfuric acid with 37.4% of concentration in mass.
1 gallon is 3785.41 ml and according the formula M=D*V = 1.31 * 3785.41 = 4958.89 grams of solution.
Only 37.4% of the solution is sulfuric acid, that is 4958.89 * 37.4/100= 1854.62 grams
Then the number of grams of sulfuric acid is 1854.62 gr.</span>