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3 years ago

What functional group is found in an alcohol?

Chemistry

1 answer:

Contact [7]3 years ago

5 0

Answer:

an alcohol is a Hydroxyl group due to the OH~ that is associated with it's molecules

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The negatively charged particles of an atom are the

posledela

Answer:

Electron: A negatively charged particle found circling or orbiting an atomic nucleus. An electron, like a proton is a charged particle, although opposite in sign, but unlike a proton, an electron has negligible atomic mass. Electrons contribute no atomic mass units to the total atomic weight of an atom.

Explanation:

3 0

3 years ago

Is kp or kc larger (both at 300 k) for the reaction 2 nh3(g) ⇀↽ n2(g) + 3 h2(g) ? 1. they are both the same. 2. kc is larger. 3.

fgiga [73]

The equation is 2 NH3 (g) â‡€â†˝ N2 (g) + 3 H2 (g)
Difference in the number of moles delta n = ((3 + 1) - 2) = 4 - 2 = 2
We have an equation Kp= Kc (R x T) ^ (delta n); R is constant and T = 300 K
Kp / Kc = (R x T) ^2 Based on the temperature value (300 K), we can conclude that Kp is Larger.

5 0

3 years ago

Ions can have a positive or negative charge. false or true

Fudgin [204]

True. Ions can have a positive or negative charge.

7 0

3 years ago

Read 2 more answers

3.0 cm x 4.0 cm x 1.0 cm [?]cm^3

CaHeK987 [17]

Explanation:

Hi there!!

you asked to multiply these all right,

you can simply multiply it ,

=3cm × 4 cm × 1cm

= 12cm^2×1cm (4×3=12)

= 12cm^3 (12×1=12)

Therefore, theanswer is 12 cm^3.

Hope it helps..

4 0

3 years ago

Bananas Foster is an example of a dessert that is flambéed. A Bananas Foster label states the accepted number of Calories to be

WINSTONCH [101]

Answer:

6.00%

Explanation:

Step 1: Given data

Accepted value for the number of calories in a Bananas Foster: 300 calories

Measured value for the number of calories in a Bananas Foster: 318 calories

Step 2: Calculate the percent error in the measure

We will use the following expression.

%error = |accepted value - experimental value|/ accepted value × 100%

%error = |300 cal - 318 cal|/ 300 cal × 100% = 6.00%

4 0

3 years ago